5. A 3-phase, 50 Hz, star - connected, 2000 - KVA, 2300-V alternator gives a short circuit current of 600 A for a certain field excitation. With the same excitation, the OC voltage was 900 V. The resistance between a pair of terminals was 0.12 . Find the full load regulation at (a) UPF (b) 0.8 pf lagging and (c) 0.8 pf leading [7.3% ; 23.8 %; -13.2%]

The circuit on the right has several resistors and ca- pacitors, as well as an ideal ammeter. The battery is assumed to have negligible internal resistance. Right after the switch is closed: a) What current I₁ does the ammeter read? b) What power P₁ is being dissipated by the 50.0 2 resistor? What charge Q₁ is stored on the 10.0 µF ca- pacitor? After a long time has passed: c) What current I2 will the ammeter read? d) What power P₂ will the 50.0 2 resistor dissipate? What charge Q2 will be stored on the 10.0 μF capacitor? 100.0 V 25.0 Ω |75.0 Ω 15.0 με www 20.0 μF 50.0 ΩΣ www 15.00 25.0 Ω 10.0μF $25.0 2

b) The unknown resistance is determined by Wheatstone bridge and is given by Rx = R. where R; = 90 = 0.5% 2 R; = 900 = 0.8% 2 R; = 825 = 0.6% 2 Determine the magnitude of the resistance and the limiting error in % and ohms for the unknown resistance R.

provide implicit general solution, show all steps please

How can I simplifie this circuit ?

Handwrite and step by step solution

Full detailed answer please

In the circuit shown in the figure below, C1=43µF, C2=33µF, C3=22µF, and a voltage Vab=43V is applied accross points a and b. After C1 is fully charged, the switch is thrown to the right. What is the final voltage on C3? Express your answer in units of V(Volts) using one decimal place. a C2 C3 b

In the node-voltage method, when a dependent voltage source connects two essential nodes, how can this situation be handled? A. The dependent source and its two ends are treated as a supernode for which a single KCL equation can be written. B. The two essential nodes are temporarily treated as having the same voltage. C. The dependent source is temporarily treated as an open circuit. D. The KCL equation is written for only one of the two essential nodes, and a KCL equation is written for the reference node. E. None of the provided options.

(a) Use Ohm's Law to derive an expression relating Vout to Vin using the values of the two resistors. For this calculation, assume that you have no load attached (i.e. RL → xx). Make sure to explain in words each step you take. Hint: Vout is just the voltage drop across R2. You can draw in a battery with AV = Vin if that helps you set up the relationships. R1 Vin R2 Vout (O Vin- Your answer should be in the form, Vout The term in parentheses is called the gain of the divider, or the divider ratio. in· ww