(5) You have sampled a population of lady beetles, in which black spots (B) is dominant to no spots (b). You know that the percentage of individuals with the homozygous recessive genotype is 32%. Use that information to calculate the genotype frequency of the BB genotype and the Bb genotype.

Lets say there exists a gene  in the United States that comes in two alleles, the dominant A and the recessive a.  The allele frequency of the dominant allele is 60% and the allele frequency of the recessive allele is 40%  The population in genotyped and its found in the United States there are 36% Homozygous Dominant folk, 48% Homozygous Recessive folk, and 16% Homozygous recessive folk.  Do you think there is any fitness advantage to any of these genotypes?  Why or why not? View keyboard shortcuts

You are examining a population of snakes in which 20% of the individuals exhibit the recessive phenotype for albinism. If albinism is exhibited only by the genotype aa, how many snakes out of a population of 100 would you expect to CARRY the albinism allele (so be Aa), but be normal color?

Butterflies show 3 phenotypes due to incomplete dominance at the D locus with alleles DY and DB giving green phenotype in heterozygotes and yellow and blue in homozygotes         b) In another population only 1% of the butterflies are blue, What is the DY allele frequency?

Answer the question, using the graphs attached.

There is a gene that causes people to have crumbly earwax. This gene is expressed as a complete dominant: Individuals who are homozygous dominants (CC) or heterozygous (Cc) have crumbly earwax. Homozygous recessives (cc) have gooey earwax. There are 100 people, 64 of whom have crumbly earwax. Assuming Hardy-Weinberg conditions, what is the frequency of the c allele on Paradise Island? Group of answer choices 0.80 This cannot be answered without more information. 0.60 0.36 None of the above.

Snow geese (Chen caerulescens) come in two color types, white “snows” and “blues” with dark bodies. A single gene controls coloration, where the dark (“blue”) allele (D) is dominant. A population of 30,012 geese includes 9236 dark individuals. Genetic testing reveals that 7636 of the 9236 dark individuals are heterozygous (Dd). According to the Hardy-Weinberg equilibrium, what is the expected frequency of genotype Dd? Group of answer choices A.) 0.492 B.) 0.181 C.) 0.297 D.) 0.453

In humans, there is a gene that influences the ability to smell the thioesters present in urine after asparagus is eaten. The ability to smell these compounds is an autosomal dominant trait. A is dominant and confers the ability to smell these thioesters a is recessive and does NOT confer the ability to smell these thioesters p = freq (A) = frequency of allele A in the population = number of A alleles/ total number of alleles %3D q = freq (a) = frequency of allele a in the population where p + q = 1 and, therefore, p? + 2pq + q? = 1 and %3D %D p? = freq (AA) = frequency of genotype AA = number of AA individuals/ total number of individuals %3D 2pq = freq (Aa) = frequency of genotype Aa q? = freq (aa) = frequency of genotype aa Phenotype Number of People Able to smell thioesters 378 Unable to smell thioesters 1323 Total 1701 1. Calculate p and q for this population. 2. Calculate p?, 2pq, and q? for this population.

Suppose in a certain population there are 100 individuals homozygous for the A1 allele, 400 individuals homozygous for the A2 allele, and 500 heterozygous individuals. What are the genotype frequencies? What are the allele frequencies?

In a Gecko population a group of Geckos skin color is controlled by one gene with two alleles "R"which codes for red and is dominant to "r" which codes for yellow and is recessive. If 100 Geckos are on the island and you gene test them to know their alleles you'll observe that 30 are homozygous red, 60 are heterozygous red, and 20 are homozygous recessive. Determine the Chi-square. assuming the original parents (Rr xRr).* Hint: determine the expected first before plugging into the equation awesome as this one? REGISTER NOW 13 5 11 4 D