+5 V 1 mA Ic2 IB2 Q2 Тв1 V BE Figure P12.12
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Consider the circuit of Figure P12.12 in which Q1 has IES1=10−14 A and β1=100, while Q2 has IES2=10−13 A and β2=100. Determine the values of VBE and IC2. Assume that both transistors have VT=26 mV and are operating in the active region.
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- b) Use the ALU 74181 in the figure below and the tables (one is enough; second maybe, need to check the new kit) to implement : A + B, A – B, A. B. (MSB) (LSB) 10 (MSB) F3 F2 F1 FO S3 Cn+4 16 s2 20 U14 15 S1 14 so A3 A2 A1 AO B3 B2 B1 B0 M Cn 24 23 22 21 28 27 T26 25 (LSB) (MSB) (LSB)(MSB) (LSB) And given that under M = 1 the circuit performs the following arithmetic and logic functions according to Table 11.1. Input selection S3 Output M-H S2 SI Cn=L. F3 F2 F1 FO A 1 -A В -B A&B AxB 1 A'B 1 Ax(-B) (-A)xB (-A)x(-B) 1 1 ACTIVE HIGH DATA M-L: ARITHMETIC OPERATIONS SELECTION M-H LOGIC s3 s2 s1 so Ino carry) (with carry) F-A PLUS 1 F- LA + B) PLUS 1 F- (A + BI PLUS 1 FUNCTIONS L L F-A F-A+B F-AB F-A H FA+B F-A+T F- MINUS 1 12s COMPL) F-A PLUS AB F- IA + BI PLUS AB L L L L F-0 F-ZERO F- AB F-A PLUS AB PLUS 1 F- (A + BI PLUS AB PLUS 1 L L L H L F-AOB F- AB L L F-A MINUS B MINUS 1 F-A MINUS B F- AB MINUS 1 F- A F-A PLUS AB PLUS1 F-A PLUS B PLUS 1 F- IA + B PLUS AB PLUS 1 L H L F-A PLUS AB…Rectifier Circuit. 1. What is V1 reading? a. 110V b. 220V c. 0V d. 146.67V 2. What is V2 reading? 146.67V 207.42V 0V 103.7V 3. What is V3 reading? 132V 104V 207.42V 147V Thank u.A. Determine V1 without C B. Determine V1 and VR with C C. From aB Determine V2, IL, PD D. From B determine the efficiency of the regulator (OUR SUBJECT IS INDUSTRIAL ELECTRONIC)
- - single phase half wave uncontrolled rectifier using resistive load 10 ohmand the voltage source is 120 V AC find1- maximum load current2-averge load voltage3-average load current4-RMS load current5-load power6- Power factor7-PIVFor Fixed Bias Configuration Solve for Ib, Ic and le. Atleast 2 decimal place. Be mindful of units. Assume Ic is not equal to le. ... 4 RC 15002 RB VCC 20V 90A/A 100k2 Ib=Blank 1 HA Ic=Blank 2mA le=Blank 3 mA Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answerQ1-Determine the ripple factor (r) for the filtered rectifier with a load as indicated in the figure below.What are the main benefits of using the transformer in this circuit? * 1 :1 D, Vims =130v Vpi pri ) VpMsec) f= 50 HZ RL D4 100 uF D2 2ka
- FAIRCHILD Discrete POWER & Signal Technologies SEMICONDUCTOR ru 1N4001 - 1N4007 Features • Low torward voltage drop. 10 a14 * High aurge eurrent cepablity. 0.160 4.06) DO 41 COLOR BAND DGNOTEs CAT-Cos 1.0 Ampere General Purpose Rectifiers Absolute Maximum Ratings T-26*Cuness atnerwioe rated Symbol Parameter Value Units Average Recttied Current 1.0 375" lead length a TA - 75°C Tsargei Peak Forward Surge Current 8.3 ms single halr-sine-wave Superimposed on rated load JEDEC method) 30 A Pa Total Device Dissipetion 2.5 20 Derste above 25°C Ra Tag Thermal Resistence, Junction to Amblent 5D Storage Temperature Range 55 to +175 -55 to +150 Operating Junetion Temperature PC "These rarings are imithg valuee above whien the serviceatity or any semiconductor device may te impaired. Electrical Characteristics T-20'Cunieas ofherwise roted Parameter Device Units 4001 4002 4003 4004 4005 4006 4007 Peak Repetitive Reverse Vellage Maximum RME votage DC Reverse Voltage Maximum Reverse Current @ rated VR…Question 15 In half wave rectifier with filter, if the capacitance is increased, the ripple factor increases. True False Moving to another question will save this response. ipA 120 Vp is applied to the primary coil of a center-tap transformer of turn ratio (n1 : n2 = 6: 2) . If the secondary coils are connected to a Ge diodes center-tap full wave rectifier, the output DC voltage is about __________. *1- 13.42 V2- 14.15 V3- 15.58 V4-12.54 V5- 16.23 V
- Consider a PV Module with 24 solar PV cells with the Size of each 15cm x 10cm are connected in series. Choose the correct statement for the above PV Module. (Assume necessary data) a. The output power is 2.25W and the output current is 0.09A b. The output power is 540W and the output current is 45A c. The output power is 54W and the output current is 2.25A d. The output power is 54W and the output current is 4.5A1. Identify the errors (if any) in the following full-wave rectifier circuits: a) b) D2 D2 D1 D3 D1 D3 ci R1 C1 R1 V1 Vout V1 Vout D4 D4 c) d) D2 D2 D1 D3 D1 D3 + R1 in C1 R1 C1 v1 Vout V1 Vout D4 D4 uIFind the voltage regulation of the half-wave rectifier in the Figure. VS - - jQ 9 - B Rs W lp Input port Rectifier D Output port R₁