5 kg sticky mass is moving at a constant 2 m/s towards a rod that's fixed on its right side, acting as its axis of rotation. The rod has a rotational inertia of 20 kgm2. The sticky mass collides and attaches itself to the rod 0.3 m away from its axis of rotation. The rotational inertia of the rod after the collision is (20 + mr2) where m is 5 kg and r is the distance away from the axis of rotation that the mass attaches itself to the rod. Calculate the angular velocity of the rod and mass after the collision.

Two small 0.55-kg masses are attached to opposite ends of a very lightweight rigid rod 0.7 m long. The system is spinning in a horizontal plane around a vertical axis perpendicular to the rod located halfway between the masses. Each mass is moving in a circle of radius 0.35 m at a speed of 0.85 m/s. What is the total angular momentum of this system? kg-m²/s Need Help? Read It

The figure shows a small piece of clay colliding into a disk. The disk is initially at rest, but can rotate about a pivot fixed at its center. The collision is completely inelastic.The disk has mass M = 4.84 kilograms and radius R = 0.74 meters. The clay has mass m = 285 grams and is moving horizontally at vi = 3.88 m/s just before colliding with and sticking to the disk. The clay strikes the edge of the disk at a location of b = 0.505 meters offset from the center of the disk. Note that the size of the clay is negligible compared to the radius of the disk. 1. Calculate the angular speed (rad/s) of the disk just after the collision.

A thin rod of length 2.55 m and mass 12.7 kg is rotated at an angular speed of 4.20 rad/s around an axis perpendicular to the rod and through one of its ends. Find the magnitude of the rod's angular momentum. ?kg · m2/s

In the figure, a 6.04 g bullet is fired into a 0.604 kg block attached to the end of a 0.904 m nonuniform rod of mass 0.435 kg. The block- rod-bullet system then rotates in the plane of the figure, about a fixed axis at A. The rotational inertia of the rod alone about A is 0.0372 kg-m2. Treat the block as a particle. (a) What then is the rotational inertia of the block-rod-bullet system about point A? (b) If the angular speed of the system about A just after impact is 5.03 rad/s, what is the bullet's speed just before impact? Rod Block Bullet

A turntable with a mass of 12 kg and a radius of 2 meters spins at a constant angular velocity of 140 rpm. A 500-gram scoop of uniformly-dense ice cream falls onto the turntable, so the scoop's center of mass is one meter away from the turntable's center. The scoop forms a hemisphere and has a radius of 4 cm. If there's no friction between the brick and ice cream scoop and they spin at the same angular speed, what is their final angular speed, in rev/min or in rad/s? Justify your answer with your rationale and equations used. Moments of Inertia: Idisk =MR for rotation about its center of mass parallel to the z-axis. %3D Ihemisphere = MR for rotation about its center of mass parallel to the z-axis. Edit View Ansert Format Tools Table COREI

Three children are riding on the edge of a merry-go-round that is a disk of mass 110 kg, radius 1.5 m, and is spinning at 18 rpm. The children have masses of 21.2 kg, 28.4 kg, and 33.8 kg.  If the child who has a mass of 28.4 kg moves to the center of the merry-go-round, what is the new magnitude of angular velocity in rpm?

In the figure, a 5.25 g bullet is fired into a 0.547 kg block attached to the end of a 0.718 m nonuniform rod of mass 0.117 kg. The block- rod-bullet system then rotates in the plane of the figure, about a fixed axis at A. The rotational inertia of the rod alone about A is 0.0577 kg-m2. Treat the block as a particle. (a) What then is the rotational inertia of the block-rod-bullet system about point A? (b) If the angular speed of the system about A just after impact is 4.31 rad/s, what is the bullet's speed just before impact? Rod Block Bullet (a) Number Units (b) Number i Units

A lawnmower blade has a length of 0.75 m and a mass of 1.5 kg. The blade rotates around its center at an angular velocity of 500 re. The end of the blade hits a 0.25 kg croquet ball (point mass), and the ball sticks to the blade. min Before the collision, the ball was stationary. After the collision, the ball will be moving at the same angular velocity as the blade at a distance of half of the blade length from the axis of rotation. Treat the blade as a rod rotating around its center. The final angular velocity of the lawnmower blade and croquet ball combo is rad S

Three children are riding on the edge of a merry-go-round that is 162 kg, has a 1.60 m radius, and is spinning at 21.3 rpm. The children have masses of 17.4, 28.5, and 38.8 kg. If the child who has a mass of 38.8 kg moves to the center of the merry-go-round, what is the new angular velocity in rpm?