5 boys & 5 girls sit in a row randomly, then (A) Probability that 5 girls sit together = 56 10 Target: JEE (Main + Advanced) 2020/19-01-2020/Paper-2 (B) Probability that boys & girls sit alternatively = (C) Probability that all boys are together & all girls are together given that all girls are together 1 3 55 10
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- How could knowledge of probabilities be used to analysethe data given in the table?The probability of winning a prize in a game of chance is 048. What is the least number of games that must be played to ensure that the probability of winning at least twice is more than 0.95?The proportion of male students at University of Yale is known to be 65%. Assume students are randomly assigned to tutorial groups. What is the probability that there would be fewer than 8 males in a tutorial group of 25 students? (4dp) What is the probability that there would be more than 18 males in a tutorial group of 25 students? (4dp)
- Question A college has a total enrollment of 2445 students, and 469 of them are left-handed. Use a calculator to determine the probability that a survey of 53 students will find that 9 or fewer students are left-handed. Round the σp^ answer to three decimal places and all other answers to two decimal places.An average of 1 package is sent to a server in 1 second. The server, on the other hand, prepares a document using the 5 packages received. The time between packets is modeled as an exponential random variable. Let X be a random variable expressing the time it takes the server to prepare a document. The time taken to prepare a document; a) Find the probability that it is more than 10 seconds.(with detail) b) Find the probability that it is between 5 seconds and 10 seconds. (with detail)Determine the probability of getting a jack when selecting a card rabdomly from a deck of cards? Probability =
- At the close of the stock markets on a day in 2017, there were 6100 companies listed with certain stock exchanges. On this day, the probabilities of advancing, declining, and unchanged company stocks appears in the table for the two exchanges. Find the probability that a stock was listed on Exchange 2 given that it advanced. Percentage of Probability of Probability of Companies Listed Probability the Stock Stock Stocks Remain Unchanged Exchange Exchange 1 Exchange 2 Advancing Declining 0.5052 0.7237 0.2466 0.0297 0.4948 0.6009 0.3455 0.0536 Let F be Exchange 2 and E be an advance. P(F) = .4948 and P (F') = .5052 The probability that a stock was listed on Exchange 2 given that it advanced is (Do not round until the final answer. Then round to four decimal places as needed.)The table summarizes results from 976 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Driver Intoxicated? Pedestrian Intoxicated? Yes No Yes 56 86 No 245 589 If one of the pedestrian deaths is randomly selected, find the probability that the driver was not intoxicated but the pedestrian was. Please enter a decimal to 4 places.A computer system in a company has average breakdown is 6 times per month findthe probability that more than 4 break down in January 5 to February 20.
- he table summarizes results from 977 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths DriverIntoxicated? Pedestrian Intoxicated? Yes No Yes 49 71 No 222 635 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated but the driver was. Please enter a decimal to 4 places.The table summarizes results from 975 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths DriverIntoxicated? Pedestrian Intoxicated? Yes No Yes 47 75 No 252 601 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated but the driver was. Please enter a decimal to 4 places.Probability =In a factory, in a batch of 100 products, there are on average 3 of defected ones. Probability of having the first defected product at the 10th(10.) product in 100 products.