5 boys & 5 girls sit in a row randomly, then (A) Probability that 5 girls sit together = 56 10 Target: JEE (Main + Advanced) 2020/19-01-2020/Paper-2 (B) Probability that boys & girls sit alternatively = (C) Probability that all boys are together & all girls are together given that all girls are together 1 3 55 10

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Chapter1: Combinatorial Analysis
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7.
ALLEN
(C)
6.
5 boys & 5 girls sit in a row randomly, then
(A) Probability that 5 girls sit together =
i=1
(B) Probability that boys & girls sit alternatively
10
(C) Probability that all boys are together & all girls are together given that all girls are
1
3
together =
56
10
(D) A particular boy & girl sit together given that boys & girls sit alternatively
Consider equation z8 + z7 + zº + .....
option(s)
8
(A) [](2-a¹) = 511
8
Σα - ai+1|
i=0
4
= 2
Target: JEE (Main + Advanced) 2020/19-01-2020/Paper-2
=
(B)
9
25
z²+z+ 1 = 0 has a non-real root a, then choose correct
Re (a') = -1/2
i=1
K
=
Transcribed Image Text:7. ALLEN (C) 6. 5 boys & 5 girls sit in a row randomly, then (A) Probability that 5 girls sit together = i=1 (B) Probability that boys & girls sit alternatively 10 (C) Probability that all boys are together & all girls are together given that all girls are 1 3 together = 56 10 (D) A particular boy & girl sit together given that boys & girls sit alternatively Consider equation z8 + z7 + zº + ..... option(s) 8 (A) [](2-a¹) = 511 8 Σα - ai+1| i=0 4 = 2 Target: JEE (Main + Advanced) 2020/19-01-2020/Paper-2 = (B) 9 25 z²+z+ 1 = 0 has a non-real root a, then choose correct Re (a') = -1/2 i=1 K =
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