5 An object of man 5kg is released from west 1000 m above the ground and allowed to foll unobr the influence of gr- avity. Assuming that the force due to air resistance is prop- ortional to the velocity of the object with proportionality constant x = SON-sec/1 Find ١٢٣١ (a) the velocity of the object after t seconds (b) The distance the object has traveled after trecut. placed in a room which 2 hours,

A: Firstly, we add 500/85 on both sides  and then by adding 2+500/85, we get the required result.

A: Solve  5x =-5 3

A: We have to solve for x.

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A: Given that  8-2y=4               ⇒2y=8-4               ⇒2y=4                ⇒y=2…

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A: Given the equation  x5 + 17 = 35 We need to solve it. Now, x5 + 17 = 35 implies that  x5 = 35 - 17…

A: Given function  - 7 = ex+1Taking ln on both sides - ln7 = lnex+1ln7 = x+1lne…