Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Question
**Figure Description:** The circuit diagram shown is an op-amp based configuration with various resistors connected in specific configurations. Below is a detailed explanation: 1. **Voltage Source:** There is a voltage source of 6 mV connected to the circuit. 2. **Resistor and Op-Amp Setup:** - **R1 (50 kΩ):** Connected directly to the voltage source and the non-inverting input of the first op-amp. - **Op-Amp 1:** The non-inverting input (+) is connected through R1 to the 6 mV source. The output is labeled as \( V_1 \). - **R2 (10 kΩ):** Connected from the output of the first op-amp \( V_1 \) to the inverting input (-) of the same op-amp. 3. **Second Stage of the Circuit:** - **R3 (30 kΩ):** Connected from the output \( V_1 \) of the first op-amp to the inverting input of the second op-amp. - **Op-Amp 2:** The inverting input (-) is connected through R3. The output is labeled as \( V_2 \). - **R6 (40 kΩ):** Connected from the inverting input of the second op-amp to the ground. - **R4 (20 kΩ):** Connected from the output of the second op-amp \( V_2 \) to the non-inverting input of the same op-amp. 4. **Final Stage of the Circuit:** - **R5 (8 kΩ):** Connected from the non-inverting input of the third op-amp to the output of the second op-amp. - **Op-Amp 3:** The non-inverting input (+) receives input from \( V_2 \) through R5. The output is indicated as \( v_o \), which is the desired output voltage of the entire circuit. **Problem Statement:** - The task is to find \( v_o \) in the given circuit. **Solution:** - The answers provided are: - \( V_1 = 6 \, \text{mV} \) - \( V_2 = -18 \, \text{mV} \) - \( v_o = -21.6 \, \text
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Transcribed Image Text:**Figure Description:** The circuit diagram shown is an op-amp based configuration with various resistors connected in specific configurations. Below is a detailed explanation: 1. **Voltage Source:** There is a voltage source of 6 mV connected to the circuit. 2. **Resistor and Op-Amp Setup:** - **R1 (50 kΩ):** Connected directly to the voltage source and the non-inverting input of the first op-amp. - **Op-Amp 1:** The non-inverting input (+) is connected through R1 to the 6 mV source. The output is labeled as \( V_1 \). - **R2 (10 kΩ):** Connected from the output of the first op-amp \( V_1 \) to the inverting input (-) of the same op-amp. 3. **Second Stage of the Circuit:** - **R3 (30 kΩ):** Connected from the output \( V_1 \) of the first op-amp to the inverting input of the second op-amp. - **Op-Amp 2:** The inverting input (-) is connected through R3. The output is labeled as \( V_2 \). - **R6 (40 kΩ):** Connected from the inverting input of the second op-amp to the ground. - **R4 (20 kΩ):** Connected from the output of the second op-amp \( V_2 \) to the non-inverting input of the same op-amp. 4. **Final Stage of the Circuit:** - **R5 (8 kΩ):** Connected from the non-inverting input of the third op-amp to the output of the second op-amp. - **Op-Amp 3:** The non-inverting input (+) receives input from \( V_2 \) through R5. The output is indicated as \( v_o \), which is the desired output voltage of the entire circuit. **Problem Statement:** - The task is to find \( v_o \) in the given circuit. **Solution:** - The answers provided are: - \( V_1 = 6 \, \text{mV} \) - \( V_2 = -18 \, \text{mV} \) - \( v_o = -21.6 \, \text
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