5 // 2.1 [8, 9, 2, 5, 8] + [2] "fwsyqin" [2] 1.84 <= 4 range([2, 8] [1])
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- binarySearchMc1 o Language/Type: É Java parameters references Given the following sorted array of integers: // index int[] a = {-23, -5, 7 8 9 1Ø 11 12 13 9, 14, 15, 18, 23, 24, 25, 27, 34, 62, 85, 87}; 1 2 3 4 5 What indexes are examined in a search for each value, and what value is returned? sequential search for 27 examines 0, 1, 2, 3, 4, 5, 6, 7, 8, 9; returns 27 examines 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13; a. b. returns 27 с. О еxamines 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13; returns 9 d. examines 13, 12, 11, 10, 9; returns 9 examines 0, 1, 2, 3, 4, 5, 6, 7, 8, 9; returns 9 (order shuffled) е. binary search for 27 a. O examines 6, 9; returns 9 b. examines 7, 10, 9; returns 9 c. O examines 6, 10, 8, 9; returns 9 d. examines 6, 8, 10; returns 9 е. examines 6, 3, 1; returns -1 (order shuffled)def small_index(items: list[int]) -> int:"""Return the index of the first integer in items that is less than its index,or -1 if no such integer exists in items.>>> small_index([2, 5, 7, 99, 6])-1>>> small_index([-5, 8, 9, 16])0>>> small_index([5, 8, 9, 0, 1, 3])3"""12- a=[0,0,0] deftransformArray(a): a[1]=99 def main(): a=[3,5,6] transformArray(a) print (a) main() What is written on the console? A) [0,0,0] B) [3,5,6] C) [3,99,6] D)[]
- (d) In lectures, we saw two versions of a left-associative fold, foldl which is lazy in its arguments, and foldl' which applies the combining operator strictly. Explain the difference between these two versions, and use an example to illustrate why foldl' is typically preferred.• R7.6Given the definitions double primes[] = { 2, 3, 5, 7, 11, 13 }; double* p = primes + 3; draw a diagram that explains the meanings of the following expressions: a.primes[1] b.primes + 1 c.*(primes + 1) d.p[1] e.p + 1# viewGame(G, i) takes a game description G (a dictionary of the type# produced by newGame()) and an integer player index i and returns a# string that, when printed, describes the state of the game from# player i's perspective.## Example:# >>> viewGame(G, 1)# '\nPlayer2 to play (score=0):\n 1[ ] 2[ ] 3[ ]'## Note the spacing and explicit newlines, and the fact that the player# numbers use 1-based indexing even though internally the game data# structures use Pythonic 0-based indexing.
- swap_nums seems to work, but not swap_pointers. Fix it. #include <stdio.h>void swap_nums(int *x, int *y) { int tmp; tmp = *x; *x = *y; *y = tmp; } void swap_pointers(char *x, char *y) { char *tmp; tmp = x; x = y; y = tmp; } int main() { int a,b; char *s1,*s2; a = 3; b=4; swap_nums(&a,&b); printf("a is %d\n", a); printf("b is %d\n", b); s1 = "I should print second"; s2 = "I should print first"; swap_pointers(s1,s2); printf("s1 is %s\n", s1); printf("s2 is %s\n", s2); return 0; }Assume double[][] x = new double[2][5], what are x.length, and x[1].length?Write only the function definition: Implement the following function definition: int CrazyWord(char word [ ]); //input: a character array with a null character (string) //sets all of the characters in the word to lowercase letters //changes any lowercase ‘o’ letters to hashtags ‘#’ //returns the number of hashtags that are now in the word
- int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *p1- If A=[1,2; 3,4], and B=A*2; then A*B=? O [14, 30; 28,44] O [14, 30,20,44] O [14, 20; 30,44] O [14, 20; 28, 44]#include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…