(4-x2)/(3x2-x-10)•(6x)/(8x+16)

Q: (x² +5x-4) + (2x²+2x+3)

A: x2+5x-4+2x2+2x+3

Q: Convert 1/(3x-1)(3x-4) to factor polynomial Convert (2x+1)(2x+3)(2x+5) to factor polynomial

A: Convert equations into factor polynomial

Q: X^2+3x-18=(x-3)(x+a)

A: Given that x2 + 3x - 18 =( x - 3 ) ( x + a ) we have to find value of a.  For this let us first…

Q: (2x3-x-5) - (6x3+x-x+1)

A:

Q: Use polynomial divison to simplify (10x3 - 2x + 7)by(5x-4)

A:

Q: (4/5x2+1/2x+8) + (1/7x2+2/7x3+5) Add the 2 polynomials

A:

Q: Convert x/(x-9)(x-10)(x-11) to factor polynomial

A:

Q: Where and how did you get 512x -120 + 8x, then 5x^2 - 50x? Break down 12/x + 8/x-10. I get this…

A:

Q: (8x2 - 10) + (2x² - 3x - 4) 24x2 - 7x + 5) - (14x2 + 4x - 3) (x4)5

A:

Q: how did you get the (x^2+2x-3) twice? can you show that please?

A:

Q: 5x/ x2-x-12 - 2x-1 / x2-3x-4

A:

Q: 9x3-21x²+15x 3x 5.-(4-x)(6x) 4. 3

A:

Q: X^2-4x-4=(x-2)^2

A: Given:     To determine: value of x

Q: 4x^3(-x^2+2x-7)

A: To simplify the expression.

Q: (X+5)(x^2-3x-2

A: (x+5)(x2-3x-2)=x3-3x2-2x+5x2-15x-10

Q: (5x+4)(2x+5)^2+(5x+4)^2(2x+5) factor

A: Given

Q: (x^3-6x^2+10x-2)/(x^2-5x+6)

A:

Q: (6x-5x1/2-6)/(2x1/2-3)

A: Given:     6x-5x-62x-3

Q: Subtract 4x/x2-10x+21-3x/x2-11x+28

A:

Q: 2(-4x4 + 6x3 - 9x2 – 12) + 3(-3x3 + 8x2 - 11x + 7).

A: Given 2-4x4+6x3-9x2-12+3-3x3+8x2-11x+7

Q: (5x3-5x2-5x+5) ÷ (5x+1)

A:

Q: 5) (4x3 – 7x) (2x - 1)

A: Simplify Taking x common

Q: 6x+3-(8x-5)

A: Given, 6x+3-(8x-5) we have to simplify it

Q: (4x²-3x+1)-(2x²-3x+4)

A:

Q: Divide (3x4-x2-6)/(x2 -2)

A: after divide the given function the remainder is 4 and quotient is 3x^2 +5 detailed solution i given…

Q: (2k^{3}-3+7k^{2})+(8k^{3}+5k^{2}+6)

A:

Q: Divide (x4 + 7x3 - 5x2 + x - 11)/(x - 1)

A:

Q: -3x^2+5x-9 Divide by (x)

A:

Q: (102x+1)(10x-3)=1010

A:

Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.