4HCN(l) + 5O2(g) 2H2O(g) + 4CO2(g) + 4N2(g) This reaction occurs spontaneously as written when all reactants and products are in their standard states (T = 298.17 K). What is G° for this reaction in J/mol?

The element oxygen was prepared by Joseph Priestley in 1774 by heating mercury(II) oxide: HgO(s) → Hg() + 1/2O2(g), AH = 90.84 kJ/mol. Estimate the temperature at which this reaction will become spontaneous under standard state conditions. S'(Hg) = 76.02 J/K mol S(O2) = 205.0 J/K mol C S(HgO) = 70.29 J/K mol 11

Σ *00 For a particular reaction, AH = 81.95 kJ and AS = 27.0 J/K. Calculate AG for this reaction at 298 K. AG = %3D What can be said about the spontaneity of the reaction at 298 K? O The system is spontaneous in the reverse direction. O The system is at equilibrium. O The system is spontaneous as written. 8:12 PH (口 四< 11/8/20 F5 F8 F12 PrtScr Insert Delete Backspace $4 % 8. 5. 7. 24 Alt Ctri

Consider the following reaction under standard conditions, in which DHo and DSo are given.             CO(g)  +  2H2(g)  -->  CH3OH(g);          DHo = -90.5 kJ, and DSo = -219.2 J/K What is DGo if the reaction is carried out at 250oC under standard conditions? Is the reaction spontaneous under this condition?      (A) DGo = -35.7 kJ; the reaction is spontaneous     (B) DGo = 145.3 kJ; the reaction is not spontaneous     (C) DGo = -205.1 kJ; the reaction is spontaneous     (D) DGo = 24.1 kJ; the reaction is not spontaneous

For a particular reaction at 150.5 °C, AG = –392.62 kJ/mol, and AS = 692.39 J/(mol · K). Calculate AG for this reaction at -0.4 °C. - AG = kJ/mol 80 DII DD F3 F4 F7 FB F9 F10 F12 %24 & 4. 5 6 7 8 Y U H K F.

18,19 plz

A chemical engineer is studying the two reactions shown in the table below. In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 74.0 °C and constant total pressure. Then, he measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium. AH = 181. kJ AS = -499. K ? 2NO(g) N, (g) + 0, (g) AG = kJ Which is spontaneous? this reaction the reverse reaction neither

Nitrogen ΔHof (kJ/mol) ΔGof (kJ/mol) So (J/mol K) N2 (g) 0 0 191.6 N (g) 472.7 455.6 153.3 NH3 (g) -46.1 -16.5 192.5 NH3 (aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 NO (g) 90.3 86.6 210.8 NOCl (g) 51.7 66.1 261.8 NO2 (g) 33.2 51.3 240.1 N2O (g) 82.1 104.2 219.9 N2O4 (g) 9.2 97.9 304.3 N2O4 (l) -20.0 97.0 209.0 N2O5 (s) -42.0 134.0 178.0 N2H4 (l) 50.6 149.3 121.2 N2H3CH3 (l) 54.0 180.0 166.0 HNO3 (aq) -207.4 -111.3 146.4 HNO3 (l) -174.1 -80.7 155.6 HNO3 (g) -135.1 -74.7 266.4 NH4ClO4 (s) -295.0 -89.0 186.0 NH4Cl (s) -314.4 -202.9 94.6 NH4Cl (aq) -299.7 -210.5 169.9 NH4NO3 (s) -365.6 -183.9 151.1 NH4NO3 (aq) -339.9 -190.6 259.8     Oxygen ΔHof (kJ/mol) ΔGof (kJ/mol) So (J/mol K) O2 (g) 0 0 205.1 O (g) 249.2 231.7 161.1 O3 (g)…