[48] In the predator-prey system sketch the phase portrait in the first quadrant {x ≥ 0, y ≥ 0}, and determine whether each equilibrium is stable, asymptotically stable, or unstable. [48] (0,0) is unstable. (1,1/2) is stable but not asymptotically stable. 1.5 y l I' = x(1-2y), y = y(-1+x), 0.5 01

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter14: Discrete Dynamical Systems
Section14.3: Determining Stability
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48 solution provided by instructor therefore not graded work, please explain why the graph looks like that as well

[48] In the predator-prey system
= x(1-2y),
{} y = y(-1+x),
sketch the phase portrait in the first quadrant {r > 0, y ≥ 0}, and determine whether
each equilibrium is stable, asymptotically stable, or unstable.
[48] (0,0) is unstable. (1,1/2) is stable but not asymptotically stable.
1.5
0.5
of
3
Transcribed Image Text:[48] In the predator-prey system = x(1-2y), {} y = y(-1+x), sketch the phase portrait in the first quadrant {r > 0, y ≥ 0}, and determine whether each equilibrium is stable, asymptotically stable, or unstable. [48] (0,0) is unstable. (1,1/2) is stable but not asymptotically stable. 1.5 0.5 of 3
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