41. A crane has an arm length of 20 m inclined at 30deg with the vertical. It carries a container of mass of 3 ton suspended from the top end of the arm. Find the torque produced by the gravitational force on the container about the point where the arm is fixed to the crane. Given: 1 ton = 1000 kg; neglect the weight of the arm. Hint: take the force and perpendicular distance from the point where the arm is fixed to the crane. Note: Express your answer in whole number. No unit is required for the final answer. Set your calculator in radians. %3D mg p=60° r cos 60 r sin 60

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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41. A crane has an arm length of 20 m inclined at 30deg with the vertical. It
carries a container of mass of 3 ton suspended from the top end of the arm.
Find the torque produced by the gravitational force on the container about the
point where the arm is fixed to the crane. Given: 1 ton = 1000 kg; neglect the
weight of the arm. Hint: take the force and perpendicular distance from the
point where the arm is fixed to the crane. Note: Express your answer in whole
number. No unit is required for the final answer. Set your calculator in radians.
mg
0=60°
r cos 60
09 uis I
Transcribed Image Text:41. A crane has an arm length of 20 m inclined at 30deg with the vertical. It carries a container of mass of 3 ton suspended from the top end of the arm. Find the torque produced by the gravitational force on the container about the point where the arm is fixed to the crane. Given: 1 ton = 1000 kg; neglect the weight of the arm. Hint: take the force and perpendicular distance from the point where the arm is fixed to the crane. Note: Express your answer in whole number. No unit is required for the final answer. Set your calculator in radians. mg 0=60° r cos 60 09 uis I
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