1. Calculate the magnitude of the impulse during the collision.2. Calculate the magnitude and direction of the velocity of the 4.0 kg cart after the collision.3. Calculate the mass m of the second cart 4.0 m/s3.0 kgA 3.0 kg cart is moving at a speed of 4.0 m/s to the right across africtionless table, as shown above. It collides with a second cart ofan unknown mass m that is initially at rest. The magnitude of theforce Fof the collision as a function of time tis shown in thegraph below, where t= 0 is the instant of initial contact. As aresult of the collision, the second cart acquires a speed of 1.6 m/sto the right. Assume that friction is negligible before, during, andafter the collision.10Force (N)51.02.0Time (s)

mass of first cart (M) = 3 kg Initial speed of cart (v) = 4 ms (towards right)Force versus time…

Answered: 4.0 m/s 3.0 kR A 3.0 kg cart is moving…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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1. Calculate the magnitude of the impulse during the collision.

2. Calculate the magnitude and direction of the velocity of the 4.0 kg cart after the collision.

3. Calculate the mass m of the second cart

4.0 m/s
3.0 kg
A 3.0 kg cart is moving at a speed of 4.0 m/s to the right across a
frictionless table, as shown above. It collides with a second cart of
an unknown mass m that is initially at rest. The magnitude of the
force Fof the collision as a function of time tis shown in the
graph below, where t= 0 is the instant of initial contact. As a
result of the collision, the second cart acquires a speed of 1.6 m/s
to the right. Assume that friction is negligible before, during, and
after the collision.
10
Force (N)
5
1.0
2.0
Time (s)

Expert Solution

Step 1

$mass of first cart (M) = 3 k g Initial speed of cart (v) = 4 \frac{m}{s} (t o w a r d s r i g h t) Force versus time graph is provided which has a maximum force of 10 N. Initial speed of second cart = 0 \frac{m}{s} Mass of second cart = m Final speed of second cart = 1.6 \frac{m}{s}$

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