4. Write a conclusion about the results of the experiment, explaining any differences in the amount of bubbles among the different treatments. In your conclusion, use all the following terms correctly: catalase, hydrogen peroxide, breaking down, denature, enzyme, oxygen, water, products, substrate, potato
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- EUnit 6 Test: Perio x EExam EExam Roland Morris-F /e/1FAlpQLSfu77px9GCC72ITm_kzkDfi5F X8aLoFHyH_CfnKfWYPF5s7w/viewform?hr sut New folder Genetic drift-Wikip.. &Algebra Foundatio. Image result for sur. Which of these atoms has an oxidation number of 2-?* Sulfur OChlorine Aluminum Neon Silicon Sodium Phosphorus Magnesium Which of these atoms has an oxidation number of 3+?* Arsenic Selenium GalliumPart 2 must be done at a constant temperature. What steps were taken in the experiment to satisfy this requirement?THIS IS A MULTIPART QUESTION, PLEASE ANSWER ALL THANK YOU You are studying two bacterias, bacA and bacB. bacB has increased levels of peroxidase but no catalase. On the other hand, bacA has increased levels of catalase but no peroxidase. For the first experiment, you add both bacA and bacB in a buffer containing hydrogen peroxide and NO iron. After analyzing the amount of hydrogen peroxide after 1 hr in the buffer alone, then buffer with bacA, then buffer with bacB, the data below is shown. A. Oxygen levels are also being measured in each of the 3 conditions from the experiment above. Create a graph of the expected O2 level results, explain the rationale and label title with axis B. Graph the expected NAD+ level results in the 3 conditions present, explain rationale and label title with axis C. On the second experiment, everything was repeated like the first however, this time iron was added to the buffer. Create a graph of the expected oxygen levels after the addition to iron…
- 8 eBook Select all of the following that could apply to the brown curve. Enzyme concentration is higher. Temperature for an enzyme is too high. Temperature for an enzyme is optimal. Activation energy is lower. Enzyme concentration is lower. Activation energy is higher. Reactants Progress of reaction, ProductsIm currently struggling to also figure out this homework question for biology because it says A student assays a newly purchased enzyme by the standard procedure. He dissolves 50mg of the enzyme in 100mL water and uses 10mL. For the assay. He adds the enzyme to the substrate and collects absorbance was 0.345 and at 10 min absorbance was 0.645. Standard curve equation was given Y=0.238x. (I need some help in explanation and how to get it step by step)POTATO OSMOSIS (LABORATORY EXPERIMENTATION) MATERIALS: Small basin 2 medium size potatoes (fresh) Table salt Sugar Distilled water (Wilkins or H2Zero) PROCEDURE: A. POTATOES Cut the potatoes to half, making 4 pcs of potatoes Cook one of the half potatoes and set aside the 3 other potatoes Label the cooked potato as letter B. MAKING A CAVITY Make a cavity of each half potato Label the raw potato as A B and C In potato A place salt on the cavity In potato B place sugar in the cavity Leave the potato C empty. Place sugar on the cavity of potato D C. POTATO OSMOSIS - Place distilled water in the basin and arranged the potatoes inside the basin. Leave it for 1hr. Observe after an hour. Do not mind the color of the potato. QUESTIONS: 1. What is your observation from potato A to D? 2. What can you conclude by comparing potato A and potato B? 3. What can you conclude by comparing potato A and potato C?
- POTATO OSMOSIS (LABORATORY EXPERIMENTATION) MATERIALS: Small basin 2 medium size potatoes (fresh) Table salt Sugar Distilled water (Wilkins or H2Zero) PROCEDURE: A. POTATOES Cut the potatoes to half, making 4 pcs of potatoes Cook one of the half potatoes and set aside the 3 other potatoes Label the cooked potato as letter B. MAKING A CAVITY Make a cavity of each half potato Label the raw potato as A B and C In potato A place salt on the cavity In potato B place sugar in the cavity Leave the potato C empty. Place sugar on the cavity of potato D C. POTATO OSMOSIS - Place distilled water in the basin and arranged the potatoes inside the basin. Leave it for 1hr. Observe after an hour. Do not mind the color of the potato. QUESTIONS: 1. What can you conclude by comparing potato A and potato D? 2. The liquid in the cavity of some potatoes came from where? 3. What is your conclusion about the experiment?For most physiological/biochemical experiments, it is usually most desirable for cells to be in the • A. exponential phase • B. death phase C. lag phase • D. stationary phaseThree organisms were tested biochemically for their production of energy, and various compounds were measured in each organism. The amounts found are shown in relative units. Please identify what each organism is and explain why. Thanks! (chart photo attatched)
- Please answer all parts as they are related to each other 1. Cells naturally have a negative charge. What are some compounds that give cells this negative charge? 2. We wash away the dye when we make a positive stain, but not when we make a negative stain. a. What would you see in your microscope if you made a positive stain and did not wash away the dye? b. What would you see in your microscope if you made a negative stain and did wash away the dye? 3. Draw an example of what you might expect to see under the microscope if you were looking at the following microbes. Use the genus name to determine cell shape and arrangement. Remember that positive and negative stains look different as well! a. Negative stain of Diplococcus pneumoniae b. Positive stain of Streptobacilus rattiThe graph shows the volume of a gaseous product formed during two trials of a reaction. A different concentration of reactant was used during each trial, whereas the other factors were kept constant. Trial 2 Trial 1 Time Which of the following statements explains which trial has a lower concentration of the reactant? O Trial 1, because the average rate of the reaction is lower. O Trial 1, because this reaction lasted for a longer duration than Trial 2. O Trial 2, because this reaction was initially fast and later slowed down. O Trial 2, because the volume of product formed per unit time was higher. Amount of Pro ductIdentify the Boundary Condition (2) For each scenario, choose which boundary condition would be appropriate. Consider and list what assumptions you might be making. 5. In a bioreactor, enzymes are bound to glass beads. Substrates diffuse in the media to/from the beads. 6. Oxygen diffuses towards a single cell in a culture dish. It is rapidly consumed at the cell surface. 7. Crystals of active pharmaceutical ingredient (API) are mixed vigorously to dissolve them into a formulation. 8. Dissolved solute flows through a tube.