4. What is the range (sxs _) of the data values that would allow 55% of the data to fall within the mean observing symmetry? Draw the curve and show your complete solution. The Normal Distribution Activity For Data Set 2 Ar4.10; 3. Mean = 2.00 Variance = 4.5263 Standard Deviation = 2.1275 Ag 0. G E NEF or e t ns 7. Sketch the second bell curve by showing the mean and standard deviation. EN .26 TO PAL NE N teNE hart 1.6 15: -t.0 ** 10. 1945 - L6S15 x-t.10 The range of data values that will allow 55% of the data to fall within the mean of symmetry is 7.0625 and 10.3375 5. What is the variance of this data set? o? = (2.1546)? g? = 4.6423 .af e Given that the standard deviation is 2.1546 and it is the square root of the variance, 8. What is the data value (raw score) associated with a standard score of 2.08? Determine the percentage greater than this score. Draw the curve and show your complete solution. the value of the variance is 4.6423. 6. Are there any outliers with this data set? (Outliers refer to data points that lie beyond 3 standard deviation from the mean). A.cecino vers 2.5 There are no outliers with this data set since all values in the data set do not go beyond the three standard deviations from the mean. t. ceree t e er O 2.00 The percentage that is greater than the raw score of 6.4252 is 98.12%. 9. What is the data value (raw score) associated with a standard score of -1.3? Determine the percentage less than this score. Draw the curve and show your complete solution. -1- 16t x- * 0.9032 10. 81%. LE N ees The percentage that is less than the raw score of -0.7658 is 90.32%.

28 = 4 • r 7 8

2 cups of lime juice with 5 cups of water  3 cups of lime juice with 7 cups of water what has a stronger lime flavor

Subtract. 2 27 3 4 3 2 (Simplify your answer.) 27 4 II