4. The section of peripheral nerve in neck is under tension of force F=0.18N due to sudden movement that causes large deformation of the nerve. As shown in the below figure, the nerve consists of two structures: fascicles and epineurium with modulus of elasticity of Efascicles=Ef2=MPa and Eepineurium=Ee 0.5MPA. Note: you can model all three fascicles as one part with the cross section of Afascicles=A=3(t(200x10“)²)= 12 x10*. Use compatibility condition (fascicles and epineurium deform together) b) Determine the deformation of the peripheral nerve (L=50mm). Note: make sure to include the entire solution including the internal forces in fascicles and/or epineurium. d) If the nerve can tolerate strain up to 0.2, determine if the nerve got injured or not due to this sudden movement Peripheral nerve Under tension 50mm Fascicles F 400pm Epineurium 400pm 400um Cross section of peripheral nerve 1000um (Answer: 8 9.4mm )

A. A car's body has mass 100 slugs. This mass is supported by the car's 4 shock absorbers. The shock absorbers are identical vertical linear springs. Complete a FBD of the car's body (this would not include the car's wheels, axels etc. just the car's body) Each spring is compressed 1.25 inches. Determine the spring "k" value. Answer: 644 lb/inch. Find the compression of each spring if 4 people, each with mass 6 slugs, get into the car, Answer: 1.55" ii. iii.

In the graph the force versus displacement of a spring is given (the spring is shown in a separate figure--see below). The x-axis range is ±2 cm. The y-axis range is tFs, where Fs = 220 N. How much work does the spring do on the block (the mass "m") when the block moves from x₁ = 7.6 cm to 4.3 cm? W J y F. X -1.5 -0.5 0 10.5 1 1.5 -F How much work does the spring do on the block (the mass "m") when the block moves from x; = 7.6 cm to -7.6 cm? W = Question Help: Read Submit Question m

A fraternity brother finds an old bungee cord at a garage sale and is contemplating on having a bungee jump event. He measures the spring constant of the cord (assume it is a linear spring) by applying a 500 N force to it and measuring a stretch of 2.5 m. Your job is to help him estimate how tall the jump tower should be. He knows the cord is L = 40 m long, he expects the cord to stretch d for an average 60 kg guy like himself, and at maximum stretch he wants his feet to still be 10 m above the ground. Determine: a. The maximum distance, d, the cord would stretch if a 60 kg brother jumped from tower height, H. b. The force developed in the cord at his max stretch position. c. Calculate the expected tower height. d. The velocity of the brother 40 m below from the topmost level of the tower.

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Please write the problem on paper, I do not like it when it is typed out on the computer. Need help on all questions. Please include all units, steps to the problem and information such as its direction or if it is in compression or tension. Thanks!

show all steps in detail, units and formulas please.

3) A point mass is attached to one end of a beam levered against a spike which acts as the pivot. The point mass weighs 250N and the beam has a uniform mass of 10kg and is 8m long. Parts a and b Part c Fapplied 3 of 6mov 1m 8m Krist 0 = 60° Scale 250 N Scale a. If a scale placed beneath the point mass reads 250N, what is the magnitude and direction for the force at the pivot point? Direction: North, 90° from x-axis Magnitude to k* 250N = 2500 N b. For the same scenario, how far must the pivot point be located relative to the left edge of the beam? (Hint, both the boxes weight and the force from the scale act at the farthest right edge of the beam.) www.acta 0672nos onl c. The pivot is then moved to be 6m from the left edge of the beam which now makes a 60 angle with the floor. How much downward force would be needed at the left-most edge of the beam to reduce the reading on the scale to zero? (Hint: the beam is still in static eq. when the scale reads zero.)

A transmission tower (a truss) for supporting electric wires is shown. The load of wire at D is shown as force F1 at an angle of a and the load of wire at A is shown as force F2 at an angle of B. Using the values given in the table below: F1 (N) F: (N) a (deg) B (deg) w (m) h (m) Value 150 70 30 60 2 a) Find the reaction forces at supports Y and Z. b) Determine the forces supported by members DO, DM, SV, and UX and specify whether the member is in Tension or Compression. M Q B F1 F2 T W X h

Cable 1 a A Cable 2 В y If the picture does not load, click this link. The shaded shape is supported by Cable 1 and Cable 2 in the position shown (Drawing is NOT to scale). The shape has a uniform weight per unit area of 11kN/m2. Step 1: If A=1.9m, C=0.4m, x=1.2m, y=1.7m, z=3.5m, a = 67°, and B = 18°, find the value of B %3D needed to keep the shape in static equilibrium. Then solve for the tension in Cable 1 (T1) and the tension in Cable 2 (T2). Once you have evaluated your values for B, T1 and T2 it is recommended that you redraw your free body diagram with the correct dimensions, weights, and forces T1x, T1y, T2x, T2y and confirm that you do have your problem correctly in horizontal, vertical, and moment equilibrium. Step 2: Once you have confirmed that you free body diagram is in equilibrium, solve the following equation: Z= T1+T2 Write your final answer for Z (in kN) in the answer box below. Round your answer to two decimal places.