-4. T Cancer treatment A cancerous tumor in a mouse is treated with a chemotherapy drug. After treatment, the rate of change in the size of the tumor (in cm³/day) is given by the function r(t) = 0.0025e0.25t – 0.1485e-0.15t, where t is measured in days. a. Find the value of to for which r(to) = 0. b. Plot the function r(t), for 0 ≤ t ≤ 15, and describe what happens to the tumor over the 15-day period after treatment. c. Evaluate ſtº r(t) dt and interpret the physical meaning of this integral. 3

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 45SE: A driver of a car stopped at a gas station to fill up his gas tank. He looked at his watch, and the...
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Question 44 part a-c Show all work, thank you!
44. T Cancer treatment A cancerous tumor in a mouse is treated with a
chemotherapy drug. After treatment, the rate of change in the size of the
tumor (in cm³/day) is given by the function
r(t) = 0.0025e0.25t
0.1485e-0.15t, where t is measured in days.
a. Find the value of to for which r(to) = 0.
b. Plot the function r(t), for 0 ≤ t ≤ 15, and describe what happens to
the tumor over the 15-day period after treatment.
c. Evaluate ſtº r(t) dt and interpret the physical meaning of this
integral.
Transcribed Image Text:44. T Cancer treatment A cancerous tumor in a mouse is treated with a chemotherapy drug. After treatment, the rate of change in the size of the tumor (in cm³/day) is given by the function r(t) = 0.0025e0.25t 0.1485e-0.15t, where t is measured in days. a. Find the value of to for which r(to) = 0. b. Plot the function r(t), for 0 ≤ t ≤ 15, and describe what happens to the tumor over the 15-day period after treatment. c. Evaluate ſtº r(t) dt and interpret the physical meaning of this integral.
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