4. No energy is stored in the circuit below at t = 0 when the switch is closed. Find vo(t) for t≥ 0. 400 mH m 4 ΚΩ www 40 V 100 nF7 + vo(t)
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- 7. Consider the following circuit: ε = 15.0 V C₁ = 25.0 μF C2 = 35.0 μF R₁ = 45.0 52 R2 = 55.0 22 R3 = 65.0 2 R₁ E Switch ww R www After the switch has been closed for a long time, it is opened at t = 0. S C₂ HH a. Immediately after the switch is closed, what is the current through each resistor and the charge on each capacitor? b. A long time after the switch is closed, what is the current through each resistor and the charge on each capacitor? c. A long time after the switch is closed, what is the energy stored in each capacitor and the power dissipated across each resistor? d. What is the current through each resistor and the charge on the capacitor as a function of time?The switch is close for a long time, then at t = 0 it was opened. Determine the equation for the current through the capacitor for t > 0. 20V 4Ω www 1=0 652 www + 100 mF 552 +)24VQuestion 6 The switch opens at t= 0 after being closed a long time. Find the current through the inductor as a function of time. t= 0 ww 2 k. 4 mA 0.5 kO3 60 mH 5 nF
- An inductor of inductance of 2 H is connected in series to a resistor of 10 2 and a 12 v battery. What is the time constant of the circuit? O 5 s 10 s O 0.2 s O 0.6 sThe switch is open for a long time, then at t = 0 it was closed. Determine the equation for the current through the inductor for t > 0. What is the voltage across the 3 resistor 1 s after the switch is closed? 10 V 2Q ww 24 V t = 0 6Ω ell www 2 H 3ΩFor R1=8000 Q, R2=9000 Q, R3=7000 Q, R4=8000 , C1=0.002 F, C2=0.004 F & 1=0.002 A in the shown circuit, obtain the energy stored in each capacitor under dc conditions. C2 R4 I1 ER3 ŽRI C1= Energy stored in C1 (in Joule)= Energy stored in C2 (in Joule)= ww
- The circuit in Figure has been connected for a long time. If the battery is disconnected, how does it take the capacitor to discharge to 1/20 of its initial voltage? Take R₁ = 2.00 Q, R₂=4.00 Q, R3-7.00 Q, R4 = 2.00 Q and C= 5.00 uF and ε = 14.0 V. (Your result must be in us. Include 2 digit after the decimal point and maximum of 2% of error is accepted in your answer.) E R₂ R₂ BAPictured circuit inductor I current ILO is before opening switch k: E = 10 V R₁ = 20 R₂ = 10 L = 0.1 H L = 0.1 F E Select one: O a. 1 A O b. 5 A O c. 10 A d. OA R₁ k L i(t) с HI R₂The switch S has been open for a long time and is suddenly closed. Neither the battery nor the inductors have any appreciable resistance. What do the ammeter and the voltmeter read 150 ms after S is closed? 50.0 N 12.0 mH ele S 20.0 V V 12.0 mH 18.0 mH 25.0 Q A 27 A, 6.42 V 0.22 A, 8.29 V 0.22 mA, 3.66 V 2.7 mA, 3.6 V O 194.9 mA, 5.38 V elle
- An 8 pF capacitor is charged up and stored away (i.e., disconnected froma battery). The stored energy in the capacitor is 4μJ. The capacitor is then connectedto the circuit on the left in Figure 2 with the positively charged end up as shown. Thecomponent values are: R0= 2 kΩ, R1= 2 kΩ, and R2= 1 kΩ and R3= 3 kΩ.( a) What is the potential difference across the capacitor before it is con-nected to the circuit? (b) Taking the instant the capacitor is connected to the circuit ast=0 (i.e., so the circuit fort≥0 is as shown on the right), what is the potentialdifference acrossR0as a function of time?[Before calculating this you will need to simplify the circuit by considering whichresistors are in series and which are in parallel]the time (2nd occurrence) after t = 0 when the voltage is –10 VWhat is the overall capacitance between point A and B? A O B 1F O2F 3F 4F C1 2 F C2 1 F K O C3 1 F