4.) In dogs, there is a hereditary deafness caused by a recessive gene (d). A kennel owner has a male dog that she wants to use for breeding purposes if possible. The dog can hear, so the owner knows his genotype is either DD or Dd. If the dog's genotype is Dd, the owner does not wish to use him for breeding so that the deafness gene will not be passed on. This can be tested by breeding the dog to a deaf female (dd). Draw the Punnett squares to illustrate these two possible crosses. List all genotypes and phenotypes showing how many of the offspring would be normal and deaf.

The B gene codes for hair while the b gene codes for hairless. If B is dominant and b is recessive. Which of the following are possible phenotypes and their genotypes? O a. Hair Bb, Hairless BB, Hair bb O b. Hairless bB, Hair BB, Hair Bb OC. Hairless Bb, Hair BB O d. Hair BB, Hair Bb, Hairless bb O atv MacBook Air esc 80 DII DD F1 F2 F3 F4 F6 F7 F8 F9 F1C @ #3 $ & 1 3 4 7 8 9 Q W tab Y U P A aps lock H. J K L Z C V B N > t fn control option command command V * 00

8. Ability to taste PTC (phenyl thiocarbamide), a bitter chemical found in some vegetables, depends on carrying at least one dominant allele, T, for the taster trait. Non-tasters are homozygous for the recessive allele (t). Another trait, albinism, is inherited as a simple recessive in which normal pigmentation is dominant. An albino man who is a taster and has a mother who is a nontaster marries a normally-pigmented woman who is a nontaster and whose father is an albino taster. (a) What are the genotypes of the man and his wife? (b) What types of children might this couple expect? MI 900 9. In pigeons, the checkered pattern depends on a dominant allele C and plain on the recessive allele b. recessive allele c. Red color is controlled by a dominant allele B and brown by the (a) Diagram a cross between homozygous checkered red and plain brown birds. Summarize the expected F₁ and F₂ results. (b) A checkered brown female mated with a plain red male to produce 2 checkered red, parents. 2…

a. Each person inherits one copy of the Huntington's Disease gene from each parent. Explain why the negative control sample (from an unaffected individual) only produced one band.   b. Explain why the positive control sample (from an individual affected by Huntington’s disease) produced twobands.

1. Human males are more likely to be color blind than females. This is because of mutations to genes located on the X-chromosome, this is a result of these genes ___ a. being sex-linked traits and not hidden by a different allele from the other parent  b. giving females more cones and rods which allows for more vision of the color spectrum.  c. all answers are true  d. not being sorted independently

1. Red-green colorblindness is caused by a recessive allele (x) at an X-linked gene, and albinism is caused by a recessive allele (a) at an autosomal gene. A phenotypically normal woman (Sara) has a father who is colorblind, and she knows that she is a carrier for albinism. She plans to have a child with a colorblind man (Abdul) who is also a carrier for albinism. What is the probability that Sara and Abdul's child will have one of the conditions, but not both? (C. Follow the steps below to answer this question. a) What is the cross? b) What are the target genotypes? Note: it might be useful to come back to this one and double- check it after you have completed step c, below. Break this down to the single gene level by answering the following questions: a. What is the proportion of normal to albino offspring? Show the Punnett square: b. What is the proportion of normal to colorblind offspring? Show the Punnett square: d) What is the probability that Sara and Abdul's child will have one…

Hello Heliodors! (cont.) Trait A For Heliodors, having four arm-like extensions is dominant over having two. In a family of Heliodors, Hayden has four arm-like extensions like his mother Helen. His father, Harry, and sister, Holly both have two. What are the genotypes of everyone in this family of Heliodors? What is Hayden's genotype? O Not enough information to determine. AA (homozygous dominant) Aa (heterozygous) aa (homozygous recessive)

In humans, unattached earlobes (E) are dominant to attached earlobes (e). If a child is born with unattached earlobes, and a mother with attached earlobes, and a dad with unattached earlobes, what is genotype of the dad? O a. EE or Ee O b. ee O c. Ee O d. Ee or ee O e. EE

A researcher is interested in whether a disease gene is linked to an RFLP marker. A cross is made between pure breeding blind cavefish and pure breeding sighted cavefish. The lines are pure breeding. The resulting RFLP markers of the F1 offspring and the F2 (from an F1XF1 cross) offspring are shown.       If the disease gene is 10 m.u. from the RFLP marker, what proportion of the F2 will have the gel pattern shown above AND be blind? Show your work    If the disease gene is 10 m.u. from the RFLP marker, what proportion of the F2 will have the gel pattern above AND NOT be blind? Show your work

A person is heterozygous for ear shape. Ear lobes are dominant to no ear lobes. Which would be a correct way to write their genotype? Group of answer choices   A. ee B. ear lobes C. no ear lobes D. Tt E. EE