4. In celery the leaves can be curly (Dominant; L) or straight (recessive; l). Another trait is spots on the leaves. Dark green spots (G) are dominant over white spots (g). Create a

Fruit weight is controlled by 4 gene pairs. The homozygous dominant weighs 200 g while the homozygous recessive weighs 80 g. Assume that the alleles have equal contribution and have cumulative effects. The F1 and F2 of the two parents below were studied. Parent 1 - D1D1D2D2D3D3d4d4    x    Parent 2 - d1d1d2d2d3d3D4D4   Compute for the contribution of the dominant allele. Compute for the fruit weight of parental 1 and parental 2.

1. In the milotypes of wheat, 4 recessive genes for height have been identified. They have been designated as h1, h2, h3, and h4. A plant homozygous recessive for these 4 pairs of genes is 21inches tall, while a plant homozygous dominant for these 4 pairs of genes is 45 inches tall. Assume that these alleles contribute quantitatively, cumulative and equally for the height difference. A plant breeder crossed plants with genotypes of H1H1H2H2h3h3h4h4 and h1h1h2h2h3h3H4H4. Both F1 and F2 generations were observed. a. What are the heights of the parents? b. What would be the heights of the F1 plants? c. Enumerate the range of heights that you can expect in the F2 generation. Also, indicate the expected number of plants of each height. d. What would be the expected mean height of the F2 progeny?

The hart baowshows mmy trats found in pea plants A botarilst crosses two pure breeding pea plants. one with yellow seeds and one with green seeds, then ose those offspring to produce a F gensration Pea Plant Traits Hower Pod Coler Plant Size Ieated Green Purple G P Green Corstricted Yellow White Terminal Short (Owarf) a Source Pea Plaw Charocienties Mariann Ru Wikimedia Commons What would be the genotypic ratio for seed color in the F 2 generation? O 3 homozygous dominant : 0 heterozygous: 1 homozygous recessive Previous

1. A farmer crossed a round-shaped (T) and yellow-colored (Y) seed plant carrying yellow seeds (Y) and a wrinkled (t) and green-colored (g) seed plant. The traits of first plant is dominant over the second one. Fertilization of the first generation plants produced a total of 16 offsprings of the plants. What will be the genotypes and phenotypes of the offsprings. (Use punnette square to answer the question) Heterozygous lines for this cross Also, list up the Homozygous and

Fruit weight is controlled by 4 gene pairs. The homozygous dominant weights 200 g while the homozygous recessive weighs 80 g. Assume that the alleles have equal contribution and have cumulative effects. The F1 and F2 of the two parents below were studied.  Parent 1                                               Parent 2 B1B1B2B2B3B3b4b4             x             b1b1b2b2b3b3B4B4 Provide the genotype and phenotype of the F1.

Plant height is controlled by 5 gene pairs. The homozygous dominant is 200 cm tall while the homozygous recessive exhibits 80 cm height. Assume that the alleles have equal contribution and have cumulative effects. The F1 and F2 of the two parents below were studied. Parent 1 Parent 2 DID,D2D2D3D3dąd, dsds dıdıd2d2d3d3DąD4 D5D5 a. Compute for the contribution of the dominant allele. b. Compute for the height of parent 1 and parent 2. Provide the genotype and phenotype of the F1. d. Compute for the frequencies of the different individuals in the F2 using the Pascal's triangle. e. Provide the phenotypes of the F2 and their frequencies. С.

9. Radishes may be long, round, or oval in shape and red, white, or purple in colour. A long white variety crossed with a round red one produced oval, purple Fi's. The F2 progeny of F1 selfing comprised nine phenotypic classes as follows: long, red long, purple long, white round, purple 9 8 15 16 oval, red 19 round, white 8. oval, purple oval, white 32 16 round, red 9 (a) Explain the pattern of inheritance. (b) Give the genotypic and phenotypic ratios expected among the progeny of crosses between: A long, purple and an oval, purple plant. An oval, purple plant and a round, white plant How many true-breeding varieties of radish could be established?

9. In con, normal kernel are dominant to waxy kernels. If you crossed a waxy kernel plant to a heterozygous normal plant what type of seeds would be produced? Normal kernels (N), waxy kernel (n) Genotype: Nn, nn Phenotype: Normal kernels and waxy kernels Genotypic Ratio: 1:1 Phenotypic Ratio: 1:1

n pea plants, the appearance of flowers along the main stem is a dominant phenotype called axial and is controlled by the T allele. The recessive phenotype, produced by the E t allele, has flowers only at the end of the stem and is called terminal. Seedpod form iS determined by a second gene. The dominant phenotype inflated is controlled by allele C, and a recessive constricted form, produced by allele c. A pure breeding axial, constricted plant is crossed to one that is pure-breeding terminal, inflated. A. The F1 progeny of this cross are allowed to self-fertilize. What is the expected distribution of phenotypic classes among the F2 progeny? -> TTcc t난 CC x Et 1:2:1