
Chemistry
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Transcribed Image Text:4. IBr decomposes according to the reaction at 150 C:
2 IBr (g) = I2 (g) + Br2 (g)
If IBr is placed in a container at an initial pressure of 5.0 atm, what will be its
%3D
equilibrium pressure at 150°C? Kp = 8.3 x 10-3
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