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- How is a solid-state diode tested? Explain.For the circuit below, assume the diodes operate with a constant voltage drop of .7V, find Vx, Vy, VD4 and ID2. 15V 15V Allt V1 V2 R1 1k IDC 1mA Vx R2 2k ww D1N4002 Vy D1N4002 7D1 D1N4002 D2 D3 R3 1k D4 D1N4002A diode circuit is given in the below figure, in which two diodes are connected in series and their saturation currents are Is1 =10-¹6 A and Is2 =10-¹4 A. If the applied source voltage is 1 V, calculate the currents IDI and ID2 and the voltage across each diode VDI and VD2. IDI Ī Vpl + D₂ VD2
- ii) Analyse the circuit shown in below Figure. 2, assume diodes as silicon diode. Calculate: a. Vout b. IR3 c. Ip2 VCC 16V D1 D4 V3 10 V R1 2.2kQ D5 D2 Vout R3 2.8kQ IR3 Ip2 R2 4.7 kQ D3 V1 2.2 V V2 15VUsing the ideal diode model, find the output voltage for the input voltage of the following circuit and graph it in detail. (a) (b) R₁ D₁ www ww R3 D2 (a) R₁ D₁ www + + D2 R2 vo Vo R₂ (b)Q1 Assume that each diode has a turn-on voltage 0.7V in the circuit shown in Figure Q1. By using the constant voltage drop model: 1kN D1 D2 2kN 4k2 6V 3V 4V Figure Q1 a) Show that it is not possible that D1 is on and D2 is off. (Hint: show a contradiction) b) Show that both D1 and D2 are on.
- Q2:- Find the level of Vo for each circuit shown in the Figure below. Also, determine the status of each diode; if it is forward or reverses biasing. Assume all diodes are silicone with 0.7v drop. +5 V +15 V -10 V (12 Marks) R DI +5 VoK D +5 VoK DI -5 VoH -5 Vo4 D2 D2 D2 +5 VoH D3 +5 Vo4 D3 -10 VoK D4 V. -5 Vo K (a) (b)uO 9:.0 A docs.google.com * ZAIN IQ l. Q3/B: Assume an ideal diode model for all the diodes in the circuit below. calculate voltages and currents through D1 and D2 9kQ 1N1199C R2 D1 18KQ 1N1199C D3 1N1199C V2 =12 V R3 1kQ R4 5kQ 1.22 V 11 mA 0.5 A O VD1 ID1 VD2 ID2 صفحة 4 من 6Given the following circuit with VDD= 9.2 V, R=2.3 k2, then the current Iis: Use the CVD model for the diode, with VD = 0.65 V. I VDD a. 0.004000 A O b. 3.717391 A OC. 0 A d. 4.000000 A e. 0.003717 A R + VD -
- For the circuit shown in the Figure, if the diodes are silicon diodes with Vp(on)=0.7 V, and VIN=50 sin wt V, V1 =6 V and V2 = 16 V, then the value of VouTP-p) is: R, D VaN Vout v1事 2章 Oa. 25.4 V Ob. 27.4 V Oc. 29.4 V Od. 23.4 VFor circuit given in Figure 3 use Complete Diode Modeland find the voltage across R1 and R2 and total current flowing in this circuit. Given that diode forward resistance is 15 Ohms for D1 and 10 Ohms for D2, also reverse current flowing acrossD2 is 20 micro Amperes. DI Ri 50 2 D2 Rz100 N www 10 V R3150 2 wwwAssuming ideal diode the voltage across the resistor R2 in the circuit shown in the Figure is: R1 E = +12V0- 2.2k2 RE1.8kN E, = +4V A 4.0 V 7.6 V 3.6 V D 4.4 V