4. Consider the following first-order initial value problem (IVP), dy +zy = f(t), 1 y(0) = 0. dt where f(t) is given as the piecewise function: 4, 0 2 with initial condition y(2) = Y2.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**IVP Problem Overview**

**Problem Statement:**

Consider the following first-order initial value problem (IVP):

\[
\frac{dy}{dt} + \frac{1}{2}y = f(t), \quad y(0) = 0.
\]

where \( f(t) \) is given as the piecewise function:

\[
f(t) = 
\begin{cases} 
4, & 0 \leq t < 2 \\
0, & 2 \leq t < \infty 
\end{cases}
\]

Find the (unique) solution, \( y(t) \), to this IVP, evaluate \( y(4) \), and sketch the graph of \( y(t) \) on the interval \( 0 \leq t \leq 4 \).

**Steps to Solve:**

**S1:** Solve the initial value problem on the interval \( 0 \leq t \leq 2 \).

**S2:** Evaluate \( y(2) \) (label this value as \( y_2 \)).

**S3:** Solve the IVP, \( L[y] = f(t) \) for \( t > 2 \) with initial condition \( y(2) = y_2 \).

**S4:** Express your solution in piecewise form and sketch its graph on \( 0 \leq t \leq 4 \).
Transcribed Image Text:**IVP Problem Overview** **Problem Statement:** Consider the following first-order initial value problem (IVP): \[ \frac{dy}{dt} + \frac{1}{2}y = f(t), \quad y(0) = 0. \] where \( f(t) \) is given as the piecewise function: \[ f(t) = \begin{cases} 4, & 0 \leq t < 2 \\ 0, & 2 \leq t < \infty \end{cases} \] Find the (unique) solution, \( y(t) \), to this IVP, evaluate \( y(4) \), and sketch the graph of \( y(t) \) on the interval \( 0 \leq t \leq 4 \). **Steps to Solve:** **S1:** Solve the initial value problem on the interval \( 0 \leq t \leq 2 \). **S2:** Evaluate \( y(2) \) (label this value as \( y_2 \)). **S3:** Solve the IVP, \( L[y] = f(t) \) for \( t > 2 \) with initial condition \( y(2) = y_2 \). **S4:** Express your solution in piecewise form and sketch its graph on \( 0 \leq t \leq 4 \).
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