4. Calculate (a) AG°, and (b) K, for the following equilibrium reaction at 25.0 °C. PCI,(g) = PCl;(g) + Cl,(g) (c) Calculate AG for the reaction if the partial pressures of the initial mixture are PPCIS= 0.0029 atm, PPC= 0.27 atm, and PCh= 0.40 atm. (d) In which direction is the spontaneous reaction?

4. Calculate (a) AG°, and (b) K, for the following equilibrium reaction at 25.0 °C. PCI,(g) = PCl;(g) + Cl,(g) (c) Calculate AG for the reaction if the partial pressures of the initial mixture are PPCIS= 0.0029 atm, PPC= 0.27 atm, and PCh= 0.40 atm. (d) In which direction is the spontaneous reaction?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

3. Consider the following reaction: Co(g) + 2H2(g) S CH;OH(g); Kp = 2.26x10ª at 25 °C Calculate AG for the reaction at 25 °C for each of the following conditions: (a) standard conditions (b) at equilibrium (c) P (CH3OH) = 1.0 atm, P (CO) = P (H2) = 0.010 atm
Consider the following reaction, where AG =-625 J at 300 C, 2 XOG) + Oz(g) 2 X02(g) a) Determine K, at 300 °C. b) Calculate AG° at 300 °C when P(XO) = 8.0x10-4 atm, P(O2) = 0.072 atm, and P(XO2) = 9.0 atm. %3D c)Is the reaction spontaneous when carried out under the conditions in (b)? How do you know? (no points for guessing) d) At 0.00 °C, AG" = 17000 J/mol. Calculate AH and AS.
8. Gaseous nitrosyl bromide, NOBr, is formed by the reaction 2NO(g) + Br,(g) 2 2NOBr(g) At 25°C, the equilibrium constant for this reaction is K, = 116 atm-1. The reaction as written is exothermic, or heat emitting. When the following amounts of the three gases are introduced into a 1-liter flask, is the reaction spontaneous in the forward or reverse direction, or is it at equilibrium? a) 0.045 atm NOBr, 0.01 atm NO, and 0.10 atm Br, at 25°C b) 0.045 atm NOBr, 0.10 atm NO, and 0.01 atm Br, at 25°C c) 0.108 atm NOBr, 0.10 atm NO, and 0.01 atm Br, at 0°C
BaCl, · H,O(s) loses water when it is heated in an oven: BaCl, · H,O(s) = BaCl, (s) + H,O(g) AH° = 63.11 kJ/mol at 25 °C AS +148 J/(K · mol) at 25 °C Write the equilibrium constant for this reaction. Find the vapor pressure of H,O (PH,0) above BaCl, · H,O(s) at 298 K. PH,0 bar = If AH° and AS° are not temperature dependent (a poor assumption), estimate the temperature at which PH,0 above BaCl, · H, O(s) will be 1 bar. T = °C
For a certain chemical reaction, the standard Gibbs free energy of reaction at 30.0 °C is -61.4 kJ. Calculate the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K = 0 x10 S
Give typed explanation not written
A2(g) + 3B2(g) -> 2AB3(g) where the ΔGorxn is -140 kJ and equilibrium constant at standard conditions is 3.5x1024. a) If we place 0.100 atm of AB3, 0.050 atm of B2, and 0.500 atm of A2 in a container at 25oC, which direction will the reaction go (if any) to reach equilibrium? b) What is the value of ΔGrxn assuming the temperature is maintained at 25oC?
Given equilibrium constant K = 0.051, please calculate the A,G° in unit of kJ for the following reaction at 489 °C, 2 HI(g) --> H2(g) + 12(g) (R = 8.314 J/K-mol). Please keep your answer to two decimal places.
I want solutions of all parts... Otherwise I will downvote
A reaction is studied at various temperatures, and a graph of ln K ( equilibrium constants on y axis) versus 1/T (Temperature on x axis) is prepared in Excel. The equation of the line is found to be y = - 9500 x + 21.5. What is the ΔSfor this reaction in J/mol/K? (assume R=8.314Jmol⋅K)
A(g) + B(g) <--> AB(s) For the above generic equation, Kp is 15.0 at 50oC, and Kp = 25.0 at 60oC. Is this reaction endothermic or exothermic?
Calculate AG°for each of the following reactions from the equilibrium constant at the temperature given. Reaction Temperature (°C) 2000 N₂ (g) + O₂(g) →→→ 2NO (g) H₂ (g) + 12 (g) → 2HI (g) 400 CO₂ (g) + H₂ (9) → CO (g) + H₂O (g) 980 CaCO3 (s) → CaO (s) + CO2 (g) 900 Ko value 4.1 x 10-4 50.0 1.67 1.04