Answered: 4. C₁0H₁4O: IR (3200 cm ¹). ¹H NMR 8…

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4. C₁0H₁4O: IR (3200 cm ¹). ¹H NMR 8 1.2 (s, 6H), 1.6 (s, 1H), 2.7 (s, 2H), 7.2 (s, 5H).

Pushing Electrons

4th Edition

ISBN:9781133951889

Author:Weeks, Daniel P.

Publisher:Weeks, Daniel P.

Chapter3: Mechanisms

Section: Chapter Questions

Problem 118EQ

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

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Please identify the following compound based on the data provided. A good first step is to calculate the degree of unsaturation. Please explain all peaks and multiplicities.

4.
C₁0H₁4O: IR (3200 cm ¹). ¹H NMR 8 1.2 (s, 6H), 1.6 (s, 1H), 2.7 (s, 2H), 7.2 (s, 5H).

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