4. An 8 bit Analog to Digital (A/D) Converter is capable of accepting an input voltage of 0 - 10 volts. a) a. What is the minimum value of input voltage to cause a digital output change of the LSB (least significant bit) ? b. What input voltage will cause all 1's at the ADC's output? c. What is the digital output code if the applied input voltage is 7.3 volts Analog Voltage In = (Decimal Value of Dig Out) * Resolution Resolution = Vrange / 2" → 10V / 2 → 0.03906V/bit Resolution = 0.03906V/bit The minimum value of the input voltage is 0.03906V/Bit to cause a digital output change of the LSB b) The input voltage that will cause all 1's at the 8-bit ADC output will be 10V, because this is the maximum input voltage for the 8-bit ADC. c) Analog Voltage In = (Decimal Value of Dig Out) * Resolution 7.3V = (Decimal Value of Dig Out) * 0.04V/bit 182.249 (10) → 182 (10) 1822 91 → R = 0 912 45 → R = 1 - 7.3V/ (0.04V/bit) → 182.249 (10) 452 22 → R = 1 222 11 → R = 0 112 5 → R = 1 5 2 2 R = 1 2 2 1 R = 0 1+2 0 R 1 182 (10) = 10110110(2) (The digital output code) The digital output code is 10110110(2) for the input Voltage of 7.3V

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For a single-phase half-wave centre-tapped rectifier, the fundamental frequency of output voltage is__ e) two times the input frequency. f) three times the input frequency. g) same the input frequency. h) four times the input frequency.

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Please solve the following problem in step by step solution. Thank you!

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q5

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