4. A double window is constructed by two layers of glass separated by a layer of dry stagnant air (as shown in figure below). The heat transfer area of the double window is 1.7 m². The temperature at the two surfaces of the window is 20.0 °C and - 8.0 °C, and the convection effect can be neglected. S (a) T₁ (20 °C) Glass: Air: Glass: Glass kı Te Air k2 T3 X1 = 6.35 mm X2 = 3.00 mm x3 = 6.35 mm Glass T4 (-8.0 °C) kı = 0.869 W/m-K k2 = 0.026 W/m.K k3=0.869 W/m.K Calculate the heat loss through window, showing the derivation steps in detail.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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How to do a)? Answer is 366 W/m^2
4. A double window is constructed by two layers of glass separated by a layer of dry
stagnant air (as shown in figure below). The heat transfer area of the double window is
1.7 m². The temperature at the two surfaces of the window is 20.0 °C and - 8.0 °C, and
the convection effect can be neglected.
(a)
(b)
T₁
(20 °C)
Glass:
Air:
Glass:
Glass
k1
X+
Te
Air
k2
T3
X1 = 6.35 mm
X2 =
3.00 mm
X3 = 6.35 mm
Glass
k3
X3
School of Applied Science
T4
(-8.0°C)
k₁=0.869 W/m-K
k2 = 0.026 W/m.K
k3= 0.869 W/m.K
Calculate the heat loss through window, showing the derivation steps
in detail.
Calculate the temperature T2 between the glass and air
through a 100 m length of steel piping, which has an
Transcribed Image Text:4. A double window is constructed by two layers of glass separated by a layer of dry stagnant air (as shown in figure below). The heat transfer area of the double window is 1.7 m². The temperature at the two surfaces of the window is 20.0 °C and - 8.0 °C, and the convection effect can be neglected. (a) (b) T₁ (20 °C) Glass: Air: Glass: Glass k1 X+ Te Air k2 T3 X1 = 6.35 mm X2 = 3.00 mm X3 = 6.35 mm Glass k3 X3 School of Applied Science T4 (-8.0°C) k₁=0.869 W/m-K k2 = 0.026 W/m.K k3= 0.869 W/m.K Calculate the heat loss through window, showing the derivation steps in detail. Calculate the temperature T2 between the glass and air through a 100 m length of steel piping, which has an
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