4. 8х, + х2 — Хз — 8 2x1 + x2 + 9x3 = 12 X1 – 7x2 + 2x3 = -4 Solve equation system by using SOR method (w=1.1) for 3 iterations. (Use six decimal digits.)

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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initial value is (0,0,0)

4. 8х1 + х2 —- Хз —
8 =
2x1 + x2 + 9x3 = 12
7x2 + 2хз
Solve equation system by using SOR method (w=1.1) for 3 iterations.
Х1 — — — 4
(Use six decimal digits.)
Transcribed Image Text:4. 8х1 + х2 —- Хз — 8 = 2x1 + x2 + 9x3 = 12 7x2 + 2хз Solve equation system by using SOR method (w=1.1) for 3 iterations. Х1 — — — 4 (Use six decimal digits.)
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