5 Throwing Upwards: Final Velocity Going down Givens: Man x= 1.82m or O t = 1.22 or 61 V₁ = 6 m/s (5,978) Vf= want a = -9.8m) 5² V top = 0-V ₂ O=V; Vi bits lets ignore the going up part, and turn it into a drop problem V₁ = V₁² + at V₁ = gt V₁ = (-9.8) (0.61) V₁ = -5.978 1/5 -6~/5 VF=-6m/s only half the story, use half the total time (vy-v₁) = V₁ + at v² = v² + 2ax 1 Ft + at² x = (" + "/^) ₁ 10 4 Throwing Upwards: Break down Vf. Time Going Up A tua = 1.225 Givens: x = 1.82m/ t = want up V₁ = 6 m/s O top a = -9.8 m/s² 2 V f = V₁ + at 0 = 6 + (²9.5) t 6 -5.8 = -9.8 t 1615 = tup Time Going Down Time total-Time up = time down 1.22 0.61 = 0.61 seconds to come down FOR ALL Projectiles that have a total vertical displacement of zero (they launch and land at same height) The total time in air is evenly split between the time up, and the time down. Max height is achieved at half of total time (vf - vi) t V = V₁ + at v² = v² + 2ax 1 x = v₁t + = at² 2 • (³₁ +01) ₁ t 2

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Q. Using the picture given below answer the following questions N W S Start E 1. Find the total distance travelled in Path B in the figure if all of the blocks are 80 m on a side. 2. What is the magnitude of the displacement of Path D if all blocks are 80 m on a side? 3. What is the total distance travelled for Path D if each block is 140 m on a side? 4. Find the magnitude of the displacement for Path B in the figure if all of the blocks are 120 m on a side.

An engineering student throws a calculator straight up to a COVID-quarantined friend, who is leaning out a window 5.66 m above. The friend catches the calculator 0.63 s later and immediately sanitizes it and her hands. Taking up as the positive direction, find the calculator's velocity v just before it was caught. V = m/s Record your numerical answer below, assuming three significant figures. 4

I know the answer is c but can you please explain why

Activity 1.16- Projectile Motion Problems Note: Neglect air friction unless otherwise specified. Use g = +10 m/s² for the magnitude of the acceleration due to gravity. 1. You throw a snowball from a roof with a speed of 20 m/s at an angle of 36.87" above the horizontal. The ball lands at a horizontal distance of 48 meters from where you throw the snowball. Assume free fall. a. Use the diagram below and problem statement above to complete the table. Write in values if given in the problem statement (or easily calculated). Use a question mark if the value is not given in the problem statement. Use the origin and +x and ty directions shown. Ya 16-20 (0,0) ! +y 9 = 36.87 48 m Vaz- x= V₂ = b. How long is the ball in the air? Start by writing the relation you use symbolically. C How high is the roof? Start by writing the relation you use symbolically By y= Vy= d. What is the speed and direction of the snowball just before it hits the ground? Give angle relative to vertical with zero degrees…

A basketball player starts at the left end of the court and moves in a straight line toward right. His velocity graph is shown below. Answer the following: d) How far does the player move to the right? What is the player’s ending position as relative to the starting position? e) Sketch a motion diagram of the player in the 12 seconds of motion using a position reference frame. Give proper labels.

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