### Mixture Problem: Alcohol Solution**Objective**: Determine the quantity of 20% alcohol solution to be added to 40 liters of a 50% alcohol solution to achieve a 30% alcohol solution.**Question 4**: - How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution?**Table Overview**:A table is provided with three columns:1. **Solution Strength (%)**: - Lists the percentage concentration of alcohol in the solution. 2. **Liters**: - Contains the quantity in liters for each solution type.3. **Total Liters of % Acid**: - Represents the total volume of alcohol in the solution after blending.The table is divided into rows, where each row corresponds to a particular solution calculation.**Work through this problem by setting up an equation**:- Let \( x \) be the liters of 20% solution. The equation based on alcohol content can be derived from:\[ 0.2x + 0.5(40) = 0.3(x + 40) \]### Steps to Solve1. Calculate the total alcohol in each solution.2. Use the equation to find the value of \( x \).3. Fill in the table based on the solution.This exercise aids in understanding mixture problems and applying percentages in practical scenarios.

Given that : The volume of 50% alcohol solution = 40 L We have to determine the volume of a 20%…

Answered: 4) How many liters of 20% alcohol…

4) How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

### Mixture Problem: Alcohol Solution

**Objective**: Determine the quantity of 20% alcohol solution to be added to 40 liters of a 50% alcohol solution to achieve a 30% alcohol solution.

**Question 4**:
- How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution?

**Table Overview**:

A table is provided with three columns:

1. **Solution Strength (%)**:
- Lists the percentage concentration of alcohol in the solution.

2. **Liters**:
- Contains the quantity in liters for each solution type.

3. **Total Liters of % Acid**:
- Represents the total volume of alcohol in the solution after blending.

The table is divided into rows, where each row corresponds to a particular solution calculation.

**Work through this problem by setting up an equation**:
- Let \( x \) be the liters of 20% solution. The equation based on alcohol content can be derived from:

\[ 0.2x + 0.5(40) = 0.3(x + 40) \]

### Steps to Solve

1. Calculate the total alcohol in each solution.
2. Use the equation to find the value of \( x \).
3. Fill in the table based on the solution.

This exercise aids in understanding mixture problems and applying percentages in practical scenarios.

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