4- [G]=1001101100 Find the following:0 1 0 0 1 1 0 1101 100 0 1 0 0 1 110 1a- Find the [H] matrix.b- Find the code table, hamming weight and the error correction capability.c- If the received word is [R]=[1011110011], find the corrected word at the receiver.

The given question regarding the generator matrix of an LBC.In the coding concept, a code table is a…

Answered: 4- [G]= [1 0 0 1 1 0 1 1 0 0 Find the…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Q25) For NRZ code, if Eb = 9.07 pico Joule and NO =1E-12, then the bit error rate is equal to a)1E-5 b)1E-6 c)none of the mentioned d)1E-4 This multiple choice question from DIGITAL COMMUNICATIONS course.just write for me the final answer.
For the signal constellation shown below, Answer the following questions: 1. What type of modulation does this represent? 32-QAM 2. How many symbols are represented?! 3. How many bits per symbol are used? 4. If the baud rate is 50000 symbols per second, what is the bit duration? Rb = baude N baud=b Rb- 180 90 00000 00001 10001 10000 ● 00100 01100 01000 11000 11100 10100 00101 01101 01001 11001 11101 10101 00111 01111 01011 10111 11111 11011 ● · 00110 01110 01010 10110 11110 11010 • . . 00010 00011 10010 10011 270 ты Tb =(RD). ть Rb = Baud * N 0 (175) 2 2 AM = A Fe 200 Fm
8. Given the following constellation diagram: 14. for Given the onowing constellation diagram: 0100 0101 1010 Solution 0011 0001 1110 135 a) Which modulation scheme is shown? b) How many bits are represented by each symbol (N)? c) How many degrees of separation are between each symbol?
There’s only 2 possible outputs for a specific transmitter: 0V and +3V (logic low and high). Find the average power of the transmitter output if it produces a message (digital) that repeats the pattern “10110001” and is transmitted at a bit rate of 8 bits per second. Prove the answer: 4.5W.
please answer with solution Determine the “M” value and number of data bits that can be represented by a single symbol using PSK where the possible phase values per symbol can be {π/4, 3π/4, 5π/4, 7π/4}. a. M=2, N=1 bit per symbol b. M=4, N=2 bit per symbol c. M=6, N=3 bit per symbol d. M=8, N=3 bit per symbol
Question 4: а. Draw the signal constellation that used the QAM defined by the following table given below: Bit Value 000 Amplitude Phase 90 degrees 90 degrees degrees degrees 180 degrees 180 degrees 270 degrees 270 degrees 1 001 010 1 011 100 101 3 110 1 111 b. Using the constellation diagram of part (a) draw the waveform for the following bit stream 101011111001110
Question 1 [Svalan i (a) Determine the largest number for Octal number that can be expressed with 4-bit. Convert the number to a Binary number and Gray code. Table 1 shows five (5) set of numbers that represented in BCD number. Convert the numbers into Decimal number and by using Appendix 1, decode the numbers into ASCII coded message. (b) Table 1 Set A 10011000 Set B 01010001 Set C 00110110 Set D 10000100 Set E 00100111 Determine the simplified Sum-of-Product (SOP) expression for the given expression by using Karnaugh map. (c) Р(4, В,С, D) - яМ(3,7,12,13,14,15) D(5,6,11)
Q27) Quantization noise can be reduced when the size of quantization level is decreased. a. False b. True DIGITAL COMMUNICATIONS Course.
A convolutional encoder has single shift register with two stages three modulo-2 adders and an output multiplexer. The following generator sequences are combined by the multiplexer to produce the encoder output g₁ = 1 0 1 and g₂ = 110. a) Draw the encoder. b) For the message sequence m= 100 1 1, determine the encoded sequence. c) Draw the state and Trellis diagram for this code.
For the above given signal each bit is separated by a vertical line. If total time is given as 12 ms, which answer is correct? O a. Data: 0 10001101011 Modulation Rate: 2 KBaud Encoding: Manchester O b. Data: 011001011110 Data Rate: 0,08 Kbps Encoding: Differantial Manchester c. Data: 011001011110 Modulation Rate: 1 Kbps Encoding: Manchester O d. Data: 010001101011Modulation Rate: 0,17 MBaud Encoding: Manchester O e. Data: 110010111101 Modulation Rate: 2 MBaud Encoding: Differantial Manchester
please answer with solution Determine the “M” value and number of data bits that can be represented by a single symbol using FSK where the possible frequency values per symbol can be {1.2kHz, 2.4kHz, 3.6kHz, 7.2kHz}. a. M=2, N=1 bit per symbol b. M=4, N=2 bit per symbol c. M=6, N=3 bit per symbol d. M=8, N=3 bit per symbol
15,10 Signal 13,68 16 14 12 7,79 10 5,76g 1,37 1,89 2. 3. 14 Sample Number The given signal is digitized by using PCM using 4 bits. Which one is the correct data? ০ a. 000001111110001000010110 O b. 111100010010100000010110 O c. 111111011000100100010010 O d. 011111110010111001101110 e. 000101111111110100010110 Amplitude (mW)

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4- [G]= [1 0 0 1 1 0 1 1 0 0 Find the following: 0100110110 0 0 1 0 0 1 1 1 0 1 a- Find the [H] matrix. b- Find the code table, hamming weight and the error correction capability. c- If the received word is [R]=[1011110011], find the corrected word at the receiver.