4 a). For the Wheatstone Bridge network shown in Figure. Evaluate the Wheatstone Bridge network and Calculate the output voltage, if R1= 80 N, R2= 1200,and R3=160 ohm and R4=480 ohm
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- Determine VGs (in Volts) for the JFET with voltage-divider bias in the figure, given that for this particular JFET the parameter values are such that VD = 8 V. VDD R1 Rp R2 Rs Given: VDD = 13 V R1 = 6,866,086 ohms R2 = 1,008,328 ohms RD = 3,441 ohms %3D Rs = 2,613 ohmsA) CALCULATE THE VALUE OF THE LOAD RESISTANCE (RL) SO THAT ITS POWER IS MAXIMUM. B) WHAT WILL BE THE MAXIMUM LOAD POWER, PLMAX ?Which of the following statements are correct for the circuit below? Thanks to the capacitors I – C1 and C2, the voltage gain of the circuit increases. II – Capacitors C1 and C2 are coupling capacitors and provide an isolation function between AC and DC voltages in the circuit. Thanks to the III – RE resistor, the voltage gain of the circuit increases. Thanks to the IV – RE resistor, the stability of the circuit increases. The V – C3 Capacitor is a bypass capacitor and prevents the loss of voltage gain. Capacitor VI – C3 is a coupling capacitor and has no effect on the voltage gain in the circuit. VII – As the value of the source internal resistance Rs increases, the voltage gain decreases. VIII – The voltage gain decreases as the value of any RL load to be added to the circuit increases
- 1. For the voltage-divider bias configuration, determine: a. IBQ- b. IcQ- c. VCEQ d. Vc. e. VE. f. V B 16 V 3.9 k2 IcQ o Vc 62 kN VB VCEQ B = 80 IBQ OVE 9.1 k2 0.68 k2Subject: CircuitsGivenRt = 37.9529 ohm..Rcd = 3.6 ohm.Rab=2.3529ohmIt=1.58APt=94.85WV2=3.16VV4=6.32VVab=3.7175vVcd=5.688VI10=0.372AI5=0.7435AI8=0.465AI9=0.632AI6=0.348AP2=4.9928WP4=9.9856WPab=5.88WP14=34.95WPcd=8.99WP12=29.96WDetermine the approximate value of VGG of Figure 522. VDD T17V 21.8kQ V, = 9.8V %3D Q1 1MQ pss 9mA DSS V. V =-4.5V EVGG Figure 522. O-1.2 V -3.281 V O 1.453 V -1.5 V
- Pt A 6v battey, delivrers loMA to thvee resistors in faralkl, R, =1kr,R2 =2K2,R3=Rx- Calcalate: a) Current in b) Power dissipatiod by Rx and R,-[Anss 6mw, 36mn. c) Resistance ratio Rx/R--(Ans: 6/)- d) Current ratio Ii/Ix. Anst 6/4). Rx stheatis Ix Anss 1 mÁ)H.w For the circuit show n figure ca Iculate the expre ss ion of tne assume t he in i tial value of in ductor .initial value of cap acit or is zero o'lf th o'5 FFor the voltage-divider configuration of figure below, if VDD = 36 V, k = 0.2 mA/V? VT = 6 V, determine IpQ. VGSQ, and VpsQ- VDD 3 kn Ioa 22 M2 DO G Vps Vaso - S 18 MQ 1ko