4 (a) r = 1.50 m magnitude direction (b) r= 2.20 m magnitude direction b 9 -Select- (c) r= 2.50 m magnitude direction a -Select--- -Select- N/C N/C N/C (d) What is the charge distribution on the sphere? inner surface nC outer surface nC

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**Conducting Spherical Shell and Electric Field Analysis**

Suppose the conducting spherical shell in the figure carries a charge of \(3.80 \, \text{nC}\) and that a charge of \(-1.60 \, \text{nC}\) is at the center of the sphere. If \(a = 1.60 \, \text{m}\) and \(b = 2.40 \, \text{m}\), find the electric field at the following:

**(a)** \(r = 1.50 \, \text{m}\)  
- Magnitude: \(\_\_\_\_\_\_\) \(\text{N/C}\)  
- Direction: \([ \text{Select} ]\)

**(b)** \(r = 2.20 \, \text{m}\)  
- Magnitude: \(\_\_\_\_\_\_\) \(\text{N/C}\)  
- Direction: \([ \text{Select} ]\)

**(c)** \(r = 2.50 \, \text{m}\)  
- Magnitude: \(\_\_\_\_\_\_\) \(\text{N/C}\)  
- Direction: \([ \text{Select} ]\)

**(d)** What is the charge distribution on the sphere?  
- Inner surface: \(\_\_\_\_\_\_\) \(\text{nC}\)  
- Outer surface: \(\_\_\_\_\_\_\) \(\text{nC}\)

**Diagram Explanation:**

- The diagram depicts a spherical shell with inner radius \(a\) and outer radius \(b\).
- The shell carries a total charge \(Q\).
- The point charge \(q\) is located at the center of the sphere.
- Illustration of the shell with positive charge markings is shown around the outer surface.
Transcribed Image Text:**Conducting Spherical Shell and Electric Field Analysis** Suppose the conducting spherical shell in the figure carries a charge of \(3.80 \, \text{nC}\) and that a charge of \(-1.60 \, \text{nC}\) is at the center of the sphere. If \(a = 1.60 \, \text{m}\) and \(b = 2.40 \, \text{m}\), find the electric field at the following: **(a)** \(r = 1.50 \, \text{m}\) - Magnitude: \(\_\_\_\_\_\_\) \(\text{N/C}\) - Direction: \([ \text{Select} ]\) **(b)** \(r = 2.20 \, \text{m}\) - Magnitude: \(\_\_\_\_\_\_\) \(\text{N/C}\) - Direction: \([ \text{Select} ]\) **(c)** \(r = 2.50 \, \text{m}\) - Magnitude: \(\_\_\_\_\_\_\) \(\text{N/C}\) - Direction: \([ \text{Select} ]\) **(d)** What is the charge distribution on the sphere? - Inner surface: \(\_\_\_\_\_\_\) \(\text{nC}\) - Outer surface: \(\_\_\_\_\_\_\) \(\text{nC}\) **Diagram Explanation:** - The diagram depicts a spherical shell with inner radius \(a\) and outer radius \(b\). - The shell carries a total charge \(Q\). - The point charge \(q\) is located at the center of the sphere. - Illustration of the shell with positive charge markings is shown around the outer surface.
Expert Solution
Step 1

given data 

q=-1.60 nC

Q = 3.80 nC 

a=1.60 m

b=2.40 m

(a) electric field at 1.50 m is

r<aE=Kqr2                              { K=9 ×109 Nm2 /C2 }   put the values we get magnitude of electric field isE = 6.4 V/m and direction is towards the center due to negative charge at the center.

(b) Given that this is conducting spherical shell so at  r=2.20 m charge imbalance a<r<b.

so E=0

 

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