4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric constants are K 3 and K2 5. Parallel-plates have the area A= 0.7 m². The distance is d= 0.1 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (E=8.85×10-12 C²/N×m²) d. K1 A AV AV = 24 V

Delmar's Standard Textbook Of Electricity
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ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter19: Capacitors
Section: Chapter Questions
Problem 3RQ: A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted...
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4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric
constants are K, = 3 and K, 5. Parallel-plates have the area A 0.7 m2. The distance is d= 0.1 m.
A potential difference of AV = 24 V is applied to the circuit.
(a) Find the equivalent capacitance of the system.
(b) Find the potential AV1. (E=8.85×10-12 C²/N×m²)
%3D
K1
HHE
AV
Δν.
24 V
%3D
kiçin buraya yazın
ASUS
Transcribed Image Text:Figure 4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric constants are K, = 3 and K, 5. Parallel-plates have the area A 0.7 m2. The distance is d= 0.1 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (E=8.85×10-12 C²/N×m²) %3D K1 HHE AV Δν. 24 V %3D kiçin buraya yazın ASUS
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