Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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**Problem Statement:**

Consider the function \( y = e^{4 - 3x} \). Find \( y' \).

**Solution:**

To find the derivative \( y' \) of the function \( y = e^{4 - 3x} \) with respect to \( x \), apply the chain rule. 

The function is in the form \( y = e^{u} \) where \( u = 4 - 3x \).

The derivative of \( e^{u} \) with respect to \( u \) is \( e^{u} \).

Now, find \( \frac{du}{dx} \), where \( u = 4 - 3x \). The derivative of \( u \) is \( -3 \).

By the chain rule:
\[ y' = \frac{d}{dx}(e^{u}) = e^{u} \cdot \frac{du}{dx} \]

So,
\[ y' = e^{4 - 3x} \cdot (-3) \]

Thus, the derivative is:
\[ y' = -3e^{4 - 3x} \]

**Answer:**
\[ y' = -3e^{4 - 3x} \]
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Transcribed Image Text:**Problem Statement:** Consider the function \( y = e^{4 - 3x} \). Find \( y' \). **Solution:** To find the derivative \( y' \) of the function \( y = e^{4 - 3x} \) with respect to \( x \), apply the chain rule. The function is in the form \( y = e^{u} \) where \( u = 4 - 3x \). The derivative of \( e^{u} \) with respect to \( u \) is \( e^{u} \). Now, find \( \frac{du}{dx} \), where \( u = 4 - 3x \). The derivative of \( u \) is \( -3 \). By the chain rule: \[ y' = \frac{d}{dx}(e^{u}) = e^{u} \cdot \frac{du}{dx} \] So, \[ y' = e^{4 - 3x} \cdot (-3) \] Thus, the derivative is: \[ y' = -3e^{4 - 3x} \] **Answer:** \[ y' = -3e^{4 - 3x} \]
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