4-1) Compute the following arithmetic operations that are used in different stages of the previouslyexplained engineering problem:a. 5+ j4 + 3- j7b. (2j – 4)(5+j7)c. (5-j2) / (2j-5)

Answered: Image /qna-images/answer/8dbee8a1-d7a7-4244-83e1-121f2cdfd826.jpg

Answered: 4-1) Compute the following arithmetic…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Expand the following: (3q-q-¹)² (q²) O a. 9q²-q-² O b. 9q4-6q² O c. -9q²-692
Expand and simplify each of the following algebraic expressions. a) 3xy²(3x³y² – 2x2) b) (2)(3х - 6)(-3х +4)
(d) an 10"+1 +3 x 4"-1+5 is divisible by 9 for all n2 1,
-4 -5 2 -41 Compute: - 2 - 2 1 4 |
Multiply: ◄ O x-2 x+4 x²-5x+6 x²+3x-4 O 1x-3 (x-2)(x+2) O (x-3) ² O 1 (x-3)(x-1) (x-3)²
(a) Write the following expression in terms of i, perform multiplication, and simplify V=25 · V-125. Student solution. The first square root can be written in terms of i as: V-25 = The second square root can be written in terms of i as: V-125 =0 Lastly we obtain: V-25 · V-125 = (b) Compute the sum of the various powers of i: i48. 18 + i 49 +¿50 Student solution. The first power of i equals: 18 The second power of i equals: 49 - The third power of i equals: 50 The sum of these powers of i equals: 48 +
i got 15120 but it was wrong can you help me go through it again
3. Simplify. x2 + 2x – 24 x² + 11x + 30 (8x – 32) ÷ - x2 – x 6 x² + x – 12 - 2(x + 2)(x + 5) О "( + 2)(ӕ + 5) x + 4 O 8(x + 10) x + 4 O 8(x+2)(x+ 5)
Find the result for the following operations: a. z = 6 > 3+8 b. z = 6+ 3 > 8 c. z = 4 > (2 + 9) d. z = (4 < 7) +3 e. z = 4 < 7 + 3
(b) x X 4 9 -5x 3 x+3 = -5 X
Answer the following:
In this question, the correct answer is B, and I agree with it, but the answer in Step 4 and step through 2 to 4 doesn't seem right? Am I wrong?

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4-1) Compute the following arithmetic operations that are used in different stages of the previously explained engineering problem: a. 5+ j4 + 3- j7 b. (2j – 4)(5+j7) c. (5-j2) / (2j-5)