3x²-27 Eric was asked to evaluate ²+7+12 x²-4x+3 ÷ when x 0, x = -5, and x = 2. To avoid having to evaluate four quadratic polynomials multiple times, Eric decided to simplify the expression before evaluating it for the first value of x. His work is shown below in blue. 3x-27 X-4213 3x²-27 = х+7х на x²+7x112 x²-4x+3 3(x²-4) (x+4x(x+1) (x+4)(x+3) (-1)(x+4) =3(x+3)(x-3)(x+4)(x+1) (x+4)(x+3)(x-x+4) =3(x-3)(x+1) (x+4)(x-1) Now substitute O for x in the simplified expression 3(x-3)XXN) (x+4)(x-1) 360-50+1) 3(-3x1)- - (0++)(0-1) Question 8 (2 points) Listen ་ 4(-D a. Evaluate the original expression for x = 0. Be sure to show all of your steps. Paragraph B I U~ A Lato Recom 19p... T Add a Fe Record Video 4 هی 20