
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Question
Using nodal analysis, demonstrate that I1 is equal to 0.7781∠(-161.9°) A for the circuit given.

Transcribed Image Text:3Ω j2Ω 1
-
+) 12 Δον
6/01
j3Ω
+
4Ω
--
+-jΩ
Ο
Ο
3/10° A
Expert Solution

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Step 1: Labelling the nodes in given circuit
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- -d.com/webapps/assessment/take/launch.jsp?course_assessment_id=_168587_1&course_id=_69233_1&content. & A Seanav videos .Lecture Recording... 4 My Drive - Google.. * Question Completion Status: Problem Continues: In the circuit below, calculate the phase angle of the phasor current through the inductor L2 in mA. 4.7 KO -j8 KO R2 L = 20.34125.6° mA 4 KQ 4.7 KO C1 R3 R1 L1 ll j1 KO j8 KO ll E L2 Save All Answers Save and S 57°F Cleararrow_forward33.1. Define impedance and admittance in two sentences each. 33.2. Enumerate four types of complex number and its operations. 33.3. Reference to 33.2, draw the phasor diagram of each type of complex number.arrow_forwardThe simultaneous equations representing the currents flowing in an unbalanced, three-phase, star connected, electrical network are as follows: 2.4I1 + 3.6I2 + 4.8I3 = 1.2 −3.9I1 + 1.3I2 − 6.5I3 = 2.6 1.7I1 + 11.9I2 + 8.5I3 = 0 Using Gaussian elimination, solve the equations for the currents.arrow_forward
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