Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
3S-1 A line of 3 point sources of light is a distance D from a screen as shown below. three. sources D screen At point P on the screen directly in front of the three sources, the waves from all three sources arrive in phase with each other and the phasor diagram looks like: A₁ A₂ A3 Apet The difference in phase between phasors from adjacent sources is 0°. Also, the difference in phase between Act and A₁ is 0°. (The net amplitude in this case is Anet-3A where 'A' is the amplitude of each

3S-1 A line of 3 point sources of light is a distance D from a screen as shown below. three. sources D screen At point P on the screen directly in front of the three sources, the waves from all three sources arrive in phase with each other and the phasor diagram looks like: A₁ A₂ A3 Apet The difference in phase between phasors from adjacent sources is 0°. Also, the difference in phase between Act and A₁ is 0°. (The net amplitude in this case is Anet-3A where 'A' is the amplitude of each

icon
Related questions
Question
### Phasor Diagram Analysis **Description:** The diagram illustrates a basic setup for analyzing wave interference from three point sources of light. These sources are positioned linearly a distance \( D \) from a screen. At point \( P \) on the screen, directly in front of the sources, the waves are in phase. This is depicted by a phasor diagram showing three phasors \( A_1 \), \( A_2 \), and \( A_3 \) combined to form a single resultant phasor \( A_{\text{net}} \). #### Phasor Diagram Explanation: - **Phasors \( A_1 \), \( A_2 \), \( A_3 \):** These represent the amplitude of each wave individually, all in phase at 0°. - **Resultant Phasor \( A_{\text{net}} \):** The net amplitude \( A_{\text{net}} = 3A \), where \( A \) is the amplitude of each individual phasor. This occurs because the difference in phase between adjacent phasors is 0°. ### Tasks: #### (a) Phasor Diagram with 45° Phase Difference - **Diagram Needed:** Sketch a new phasor diagram where each adjacent phasor has a 45° phase difference. - **Details to Include:** An arrow indicating \( A_{\text{net}} \) with numerical angle \( \theta \) from the first phasor. #### (b) Phase Difference of 90° - **Action:** Repeat step (a) for a 90° phase difference. #### (c) Phase Difference of 120° - **Action:** Repeat step (a) for a 120° phase difference. #### (d) Phase Difference of 180° - **Action:** Repeat step (a) for a 180° phase difference. #### (e) Phase Difference of 240° - **Action:** Repeat step (a) for a 240° phase difference. This exercise helps in understanding the superposition principle and interference patterns resulting from different phase differences.
Transcribed Image Text:### Phasor Diagram Analysis **Description:** The diagram illustrates a basic setup for analyzing wave interference from three point sources of light. These sources are positioned linearly a distance \( D \) from a screen. At point \( P \) on the screen, directly in front of the sources, the waves are in phase. This is depicted by a phasor diagram showing three phasors \( A_1 \), \( A_2 \), and \( A_3 \) combined to form a single resultant phasor \( A_{\text{net}} \). #### Phasor Diagram Explanation: - **Phasors \( A_1 \), \( A_2 \), \( A_3 \):** These represent the amplitude of each wave individually, all in phase at 0°. - **Resultant Phasor \( A_{\text{net}} \):** The net amplitude \( A_{\text{net}} = 3A \), where \( A \) is the amplitude of each individual phasor. This occurs because the difference in phase between adjacent phasors is 0°. ### Tasks: #### (a) Phasor Diagram with 45° Phase Difference - **Diagram Needed:** Sketch a new phasor diagram where each adjacent phasor has a 45° phase difference. - **Details to Include:** An arrow indicating \( A_{\text{net}} \) with numerical angle \( \theta \) from the first phasor. #### (b) Phase Difference of 90° - **Action:** Repeat step (a) for a 90° phase difference. #### (c) Phase Difference of 120° - **Action:** Repeat step (a) for a 120° phase difference. #### (d) Phase Difference of 180° - **Action:** Repeat step (a) for a 180° phase difference. #### (e) Phase Difference of 240° - **Action:** Repeat step (a) for a 240° phase difference. This exercise helps in understanding the superposition principle and interference patterns resulting from different phase differences.
Expert Solution
steps

Step by step

Solved in 2 steps with 5 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer