3‑Methylbutanal undergoes an aldol reaction to form 3‑hydroxy‑2‑isopropyl‑5‑methylhexanal.Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows Step 2: A second molecule of aldehyde isadded. Complete the structure and addcurved arrows.Step 1: Add curved arrows.Select Draw Rings MoreEraseHSelect Draw Rings MoreEraseCH: о :H+H,OH: о :HHStep 3: Complete the intermediate and add curvedarrows to form the final product.Select Draw Rings MoreEraseH: о :H.:0-HHHOH 10% NaOHH.5 °CHO

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3‑Methylbutanal undergoes an aldol reaction to form 3‑hydroxy‑2‑isopropyl‑5‑methylhexanal. Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows

3‑Methylbutanal undergoes an aldol reaction to form 3‑hydroxy‑2‑isopropyl‑5‑methylhexanal. Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter6: Solutions And Colloids

Section: Chapter Questions

Problem 6.38P: 6-38 Describe how we would prepare 250 mL of 0.10 M NaOH from solid NaOH and water.

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Question

100%

3‑Methylbutanal undergoes an aldol reaction to form 3‑hydroxy‑2‑isopropyl‑5‑methylhexanal.

Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows

Step 2: A second molecule of aldehyde is
added. Complete the structure and add
curved arrows.
Step 1: Add curved arrows.
Select Draw Rings More
Erase
H
Select Draw Rings More
Erase
C
H
: о :
H
+H,O
H
: о :
H
H
Step 3: Complete the intermediate and add curved
arrows to form the final product.
Select Draw Rings More
Erase
H
: о :
H.
:0-H
H
HO
H

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