3-86. The belt passing over the pulley is subjected to two forces Fi and F, each having a magnitude of 40 N. F, acts in the -k direction. Replace these forces by an equivalent force and couple moment at point A. Express the result in Cartesian vector form. Take 8 - 45°. 80 mm 300 mm

Q6- Two forces F1=240 lb and F2=160lb act on the hip joint. Determine the resultant of the two forces and express the result as a cartesian vector. Also, find the coordinate direction angles of the resultant force. Z F1= 240 lb 75° 131 F2 = 160 lb ww 45° y

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3-21.Determine the moment about point A for the forces shown in Figure P3-21. 5 kN B 75 4 3 m 2 m- 2 KN 2 KN 5 m