38. The distance d(x) (in feet) between an observer 30 ft from a straight highway and a police car traveling down the highway is given by d(x) = 30 sec x, where x is the angle (in degrees) between the observer and the police car. d(x)\x/30 ft Observer a. Use a calculator to evaluate d(x) for the given values of x. Round to the nearest foot. 45 60 70 80 89 d(x) b. Try experimenting with values of x closer to 90°. What happens as x→90°?
38. The distance d(x) (in feet) between an observer 30 ft from a straight highway and a police car traveling down the highway is given by d(x) = 30 sec x, where x is the angle (in degrees) between the observer and the police car. d(x)\x/30 ft Observer a. Use a calculator to evaluate d(x) for the given values of x. Round to the nearest foot. 45 60 70 80 89 d(x) b. Try experimenting with values of x closer to 90°. What happens as x→90°?
Transcribed Image Text:38. The distance d(x) (in feet) between an observer 30 ft from a straight highway and a police car traveling
down the highway is given by d(x) = 30 sec x, where x is the angle (in degrees) between the observer and
the police car.
d(x)\x/30 ft
Observer
a. Use a calculator to evaluate d(x) for the given values of x. Round to the nearest foot.
45 60
70
80
89
d(x)
b. Try experimenting with values of x closer to 90°. What happens as x→90°?
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