38. OP Consider the combina- tion of capacitors in Figure Figure P16.37 Problems P16.38. (a) Find the equiva lent single capacitance of the two capacitors in series and redraw the diagram (called diagram 1) with this equivalent capacitance. (b) In diagram I find the equivalent capacitance of the three capacitors in parallel and redraw the diagram as a single battery and single capacitor in a loop. (c) Com- pute the charge on the single equivalent capacitor. (d) Returning to diagram 1, compute the charge on cach individual capacitor. Does the sum agree with the value found in part (c)? (e) What is the charge on the 24.0-aF capacitor and on the 8.00-uF capacitor? Com- pute the voltage drop across () the 24.0-aF capacitor and (g) the 8.00-uF capacitor. 37 and 36. 24.0 aF 36.0 V 4.00 aF 2.00 F 8.00 AF Figure P16.38

38. OP Consider the combina- tion of capacitors in Figure Figure P16.37 Problems P16.38. (a) Find the equiva lent single capacitance of the two capacitors in series and redraw the diagram (called diagram 1) with this equivalent capacitance. (b) In diagram I find the equivalent capacitance of the three capacitors in parallel and redraw the diagram as a single battery and single capacitor in a loop. (c) Com- pute the charge on the single equivalent capacitor. (d) Returning to diagram 1, compute the charge on cach individual capacitor. Does the sum agree with the value found in part (c)? (e) What is the charge on the 24.0-aF capacitor and on the 8.00-uF capacitor? Com- pute the voltage drop across () the 24.0-aF capacitor and (g) the 8.00-uF capacitor. 37 and 36. 24.0 aF 36.0 V 4.00 aF 2.00 F 8.00 AF Figure P16.38

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Chapter1: Units, Trigonometry. And Vectors

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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

90.0 V
38. GP Consider the combina-
tion of capacitors in Figure
P16.38. (a) Find the equiva-
lent single capacitance of
the two capacitors in series and redraw the diagram
(called diagram I) with this equivalent capacitance.
(b) In diagram 1 find the equivalent capacitance of the
three capacitors in parallel and redraw the diagram as
a single battery and single capacitor in a loop. (c) Com-
pute the charge on the single equivalent capacitor.
(d) Returning to diagram 1, compute the charge on
cach individual capacitor. Does the sum agree with the
value found in part (c)? (e) What is the charge on the
24.0-uF capacitor and on the 8.00-uF capacitor? Com-
pute the voltage drop across (f) the 24.0-seF capacitor
and (g) the 8.00-uF capacitor.
Figure P16.37 Problems
37 and 56.
24.0 uF
$6.0 V
4.00 aF 2.00 F
8.00 uF
Figure P16.38

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