**Problem 37:** An object of height 8.00 cm is placed 25.0 cm to the left of a converging lens with a focal length of 10.0 cm. Determine: (a) The image location. (b) The magnification. (c) The image height. (d) Is the image real or virtual? (e) Is the image upright or inverted? **Figure P23.36:** [The figure referenced is not available.]

A concave cosmetic mirror has a focal length of 26 cmcm . A 3.0 cmcm -long mascara brush is held upright 13 cmcm from the mirror. Use ray tracing to determine the location of its image in cm. Use ray tracing to determine the height of its image in cm. Is the image upright or inverted? Real or virtual?

Ch. 35

You got a spherical concave mirror with focal length (f) of 15.0 cm. (a) Locate the image (q) and find the magnification for an object distance (p) of 30.0 cm in front of the mirror. Determine whether the image is real or virtual, inverted or upright, and larger or smaller. (b) Do the same for object distances of 15.0 cm Group of answer choices 1. (a) q = 30 cm, Image is virtual, upright, of same size, M = 1. (b) q = infinity, real, undefined, M = 2 2. (a) q = 30 cm, Image is real, inverted, of same size, M = 1. (b) q = infinity, virtual, undefined, M = undefined 3. (a) q = 15 cm, Image is real, upright, double of the object size, M = 2. (b) q = infinity, real, undefined, M = undefined 4. (a) q = 45 cm, Image is real, upright, of same size, M = 1. (b) q = infinity, virtual, upright, M = undefined

16.

A mirror has f = −1.50 m. A real object is 0.850 m away from the mirror. Where is the image?   can you please also include a picture to help me better understand? thank you

8. On one side of a converging lens of focal length 59.1 cm, you position an object of height 3.02 cm somewhere along the principal axis. The resultant image has a height of 15.10 cm. How far from the lens is the object located?     70.9 cm     28.4 cm     92.2 cm     42.5 cm