360 V DC serial motor has a starting current value of 60 A. Total armature resistance (Ra) value is 2 times serial field circuit total resistance (Rs) for this motor. And full load line current value (I) is 0.1 times starting current 1.). Motor is rotating with 1000 rpm value under full load conditions. Find the EA (reverse EMF), armature torque (Ta), armature power (Pa) values for this motor. If the load of this motor is changed till having a line current value as 10 A, find the new speed value of this motor as rpm (n2) and new armature torque (Ta2) values for this situation. Be careful about your solutions to be written readable and write the answers as it was shown below inside boxes.) EA=? Ta=? Pa=? n2 =? Ta2=?

Electromechanical energy conversion (100 V DC serial motor has a starting current value of 50 .A Total armature resistance (Ra) value si 4times of serial field circuit total resistance (Rs) for this motor. And rated load (full load) line current value si I=5 A. Motor si rotating with 600 pm value under rated load conditions. Find the starting resistance (Rst) for this motor to be connected befween the electrical source and the motor, to limit the starting current to 10 A. Find the internal generated voltage (Ea) value under rated load (full load) conditions. If the load of this motor is changed till having aline current value of 2 A, find the new speed value of this motor in rpm (n2). Write the answers inside boxes below.) Rst = Ea= n2=

1. The rotor resistance and reactance per phase of a three-phase wound rotor induction motor are 0.035 and 0.15 ohm respectively. If an additional resistance is added, the starting torque is one half of maximum torque and the full load torque is three-fourth of the maximum. Determine the following: a. Full load speed b. speed at maximum torque c. value of additional resistance per required to achieve these conditions.