36. A convex, spherical glass lens is in contact with a horizontal glass plane. The lens is illuminated from above (along its axis) with light that has a wavelength of 489 nm. When viewed from above, a pattern of fringes is observed, with a central dark circle of diameter - 6.9 mm. What is the radius of curvature of the lens? Hint: Consider the boundary of the dark circle to be at the location of the first bright ring. A) 9,7 m B) 24 m 49 m D) 97 m E) 190 m

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Chapter1: Units, Trigonometry. And Vectors
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36. A convex, spherical glass lens is in contact with a horizontal glass plane. The lens is
illuminated from above (along its axis) with light that has a wavelength of 489 nm. When viewed
from above, a pattern of fringes is observed, with a central dark circle of diameter = 6.9 mm.
What is the radius of curvature of the lens?
Hint: Consider the boundary of the dark circle to be at the location of the first bright ring.
A)
9,7 m
B) 24 m
49
m
D) 97 m
E) 190 mi
Transcribed Image Text:36. A convex, spherical glass lens is in contact with a horizontal glass plane. The lens is illuminated from above (along its axis) with light that has a wavelength of 489 nm. When viewed from above, a pattern of fringes is observed, with a central dark circle of diameter = 6.9 mm. What is the radius of curvature of the lens? Hint: Consider the boundary of the dark circle to be at the location of the first bright ring. A) 9,7 m B) 24 m 49 m D) 97 m E) 190 mi
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