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Q: 3952 3952 3952 1/2048 F lo V 0.SH euw

A: Given As there is no initial condition given in the circuit so inductor will be open circuited and…

Q: 10000 N 10000 0 3300 T3. 3V Ts.ov 1. TMAGES NOTES UTTC

A:

Q: 2.5 m 0.4 cm a) 1374 N b) 1978 N c) 2693 N d) 3517N

A: Explanation: “Since you have asked multiple questions, we will solve the first question for you. If…

Q: Find the t0tal resistance 1900n 1200n 2200 1800n 33002 4700 82000 68002 5600n

A:

Q: Rl = 20 2 1A 20 V TS RL = 10 S 4:26 Find: IL

A:

Q: 0,5V 20052 VÀ 5002 1OKSL 1002 5K2 7002 0. SV= 30052 1k2 20K. Vc

A: Op-Amp- Op-amp is a linear analog IC having 8-pins. It is fabricated using VLSI.When op-amp is used…

Q: (a) x(t)= 2 cos(2.1 n) (b) x(t)= e02.4t) + 2 e(3.6t) (c) x(t)= cos(5 t2)

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Q: 20/60° V Vị 4Ω V2 15/0° V j4 N -j1N 2Ω ll

A: The given circuit diagram is:

Q: A 52 122 →ュ 152 4V bv う H.

A: Thevenin's theorem states that any linear network with multiple sources and resistors can be…

Q: 1012 W 15.12 15 u M M R

A:

Q: Q3/Full the following blanks (15)10 ()Gray=( )BCD(5321)=( )EX-3 O O None of them O O (15)10…

A:

Q: R1 20 R3 R2 100 V 80 240Vpk 60HZ C2 = 20μF L3 6H

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Q: Vcc=20 V 56 k2 B=200 To=4010 8.2 k2 2 k2

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Q: 1652 ww R₂=452 Ru= 352 8v R3= 2√2

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Q: 7.2 N 6 N { 30 N 364 2 10 N

A: Referring to the above circuit the last two branches are connected in parallel, where 10-Ohm and…

Q: 82Ω 1002 1502 I (mA) V(volt) (12 10V 822 1002 1502

A: The solution can be achieved as follows.

Q: a I1 620°A V.0790 212 20 I4 I3 ell ji2 b 10 20 420°A -j207 Is I2 e

A: The solution is given below

Q: 422 622 R₂ 352 R3 M 432 E₂ ·lov

A:

Q: 920 V Rp 2 k2 D Ipss= 12 mA RG 1 M2 V Z 1.5 V + ネ

A:

Q: 100 N 100 2 100 2002 100 N 21002 100 S2002 100 n 1002

A: According to question: As the circuit is symmetrical about x-axis so no current flows though the two…

Q: Q2. Find the value of V. 402 j202 8V. 602 9/0° A

A: The given circuit is:

Q: r(t) + s+ 2 y(t) k s(s – 1)(s + 4) Determine the range of k for stability.

A:

Q: s + 3 2 (s + 1) (s + + 2)

A: The given function is s+3(s+1)^2 (s+2). We have to calculate its inverse laplace transform

Q: 2/0° Α (Y + 1) Ω (W + 3) Ω j2 Ω m 10/90° V j4 Ω Η 4/0°A 31 ΤΩ

A: For the above given electrical circuit we need to calculate the unknown value of current Io. In mesh…

Q: R(s) K S pote 1 1 2s² 4 1 s+1 C(s)

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Q: (x + y) 108 2 ww A 100 2 (х —Z) ! 100 V 300 NE E (x + y) 100 2 D (y + z) C N 500 2 U 009

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Q: find the value of k to get make the system stable. R(s) E(s) C(s) G1(s) H(s) K G1(s) = s(s + 11)(s +…

A: Given values, G1(s)=KS(S+11)(S+19)H(s)=1S

Q: 3000 3000 9000 V1 12V R3 R5 6000 0.9kQ R6 9000 56.2 mW P loss in R3 37 mW 43.7 mW 60 mW

A:

Q: I2 14 16 Wr 300mF 40.2 202 302 102 I5 50mH1, 602 E2 E1 0.5 F +

A: To solve the above question, one should understand the behavior of inductor and capacitor in a DC…

Q: 4Ω 4A 82 R1 52

A: As per the policy i have solved the 1st one.

Q: R1 C1 HH 100uF 10% 1000 V1 24Vpk 60HZ 0° C2 =4.7pF R2 C3 26.70 1µF

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Q: 800 V R2 R3 2000 N 100 N .500N

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Q: a 3.0 50 b 50.2 4.2 C 1002 20 d e E250 750

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Q: 2 H 2 N V S22 iz(t) i1(t) 2 H

A: Given

Q: C₁ viat Г Z₁ RG 2 ΜΩ m² RD 2.5 ΚΩ Rs 560 +16V Figure Q3 Cs C₂ HE Zo m² RL V 3 ΚΩ

A: Given JFET circuit We have to draw AC small signal equivalent circuit of given FET. FET has very…

Q: d=0.8 B=1.6T R1=25 R2=10 R3=10 E=120V m=100g

A: According to question: Just after the switch is closed inductor will acts as open circuit. The…

Q: d) Current across R25: R21 80 R23 V1 200 24V R26 R25 2 200 R24 100 500 200

A:

Q: &McQ: 1) The powerin the ccvs is C . )w sa)16 (b)32 (C)8 (d)4 24V Figc 41x Ix ....

A: The power across any element can be determined as the product of voltage across that element and…

Q: R3 500 R2 Vb R4 Va 710 200 V1 R1 350 11 1A 80V

A: Find explanation below

Q: L1 300uH L3 L4 L5 10mH 20mH 10mH L2 12mH

A:

Q: i1(t) 1502 liL(t) lic(t) + vi(t)12u(t) A 300 V 300 2 40 H 1 mF

A: Given :   In the above given question they are asking to calculate the value of inductor current at…

Q: 5202 1202 R3 2202 R1 R2 B 5002 120Ω

A:

Q: j162 j40 2g j40 2 24 2 DO V/30 キーji2 j4 2 =-0 -j10 2= j9 2 10Ω 32 82 ee

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Q: R1 R2 1 4 152 11 R4 5A 102 3. R3 5 202

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Q: 24 Ω 120 N 60 N 750 V 343 N 14 N 20 Ω

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Q: Factor to obtain a product of sums: 1) AB + A'B'C + B'C'D + BC'D'             (4 sums) 2) A'C'D +…

A:

Q: x[n] = (;) Osns2 72 h[n] = (;)" . Osns2

A:

Q: Obtain the GS of: [2x + ycos (xy)] dx + x cos(xy)dy = 0 a. xcos2y – ½ sin2y + C = 0 b. xcos2y+ ½…

A:

Q: 2052 352 25V (120102 55L lo52 lo 52 ise 12A lo2

A: Currrent flow VAD terminal is 12 amps this outgoing current of the network

Q: a 3.0 50 b 50.2 4.2 C 1002 20 d e E250 750 f

A:

Compensation Techniques

The compensation techniques are the methods that are employed in the electrical control systems to enhance the performance of the system. The performance are generally affected by the factors like lag in the compensating devices, slow response of the system of the components like sensors used in the control system. The basic compensation technique involves lag compensation, lead compensation or the combination of the both.