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35. a(t) 36 g(t) = cos 2t; v(0) = 5; s(0) = 7 2t

35. a(t) 36 g(t) = cos 2t; v(0) = 5; s(0) = 7 2t

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.7: More On Inequalities
Problem 44E
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Question (35) and (36) only. Thank you!

 

29-36. Position and velocity from acceleration Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity, and initial position. Use the Fundamental Theorem of Calculus (Theorems 6.1 and 6.2). 29. a(t) = -32; v(0) = 70; s(0) = 10 30. a(t) = −32; v(0) = 50; s(0) = 0 31. a(t) = -9.8; v(0) = 20; s(0) = 0 32. a(t) = et; v(0) = 60; s(0) = 40 33. a(t) = −0.01t; v(0) = 10; s(0) = 0 ; v(0) = 20; s(0) = 10 20 34. a(t) 2 (t + 2)² = 35. a(t) = cos 2t; v(0) = 5; s(0) = 7 2t 36. a(t) = (t² + 1)² ; v(0) = 0; s(0) = 0
Transcribed Image Text:29-36. Position and velocity from acceleration Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity, and initial position. Use the Fundamental Theorem of Calculus (Theorems 6.1 and 6.2). 29. a(t) = -32; v(0) = 70; s(0) = 10 30. a(t) = −32; v(0) = 50; s(0) = 0 31. a(t) = -9.8; v(0) = 20; s(0) = 0 32. a(t) = et; v(0) = 60; s(0) = 40 33. a(t) = −0.01t; v(0) = 10; s(0) = 0 ; v(0) = 20; s(0) = 10 20 34. a(t) 2 (t + 2)² = 35. a(t) = cos 2t; v(0) = 5; s(0) = 7 2t 36. a(t) = (t² + 1)² ; v(0) = 0; s(0) = 0
29. 31. 33. 35. L 37. v(t) = -32t + 70; s(t) = -16t² + 70t + 10 v(t) = -9.8t +20; s(t) = -4.9t² + 20t 1 1 v(t) t³ + 10t 600 - t² + 10; s(t) = - 1 4 200 1 v(t) = sin 2t + 5; s(t) 2 a. s(t) = 44t² b. 704 ft c. √30 5.477 s 5√33 d. ≈ 2.611 s 11 e. Approx. 180.023 ft cos 2t + 5t + 29 4
Transcribed Image Text:29. 31. 33. 35. L 37. v(t) = -32t + 70; s(t) = -16t² + 70t + 10 v(t) = -9.8t +20; s(t) = -4.9t² + 20t 1 1 v(t) t³ + 10t 600 - t² + 10; s(t) = - 1 4 200 1 v(t) = sin 2t + 5; s(t) 2 a. s(t) = 44t² b. 704 ft c. √30 5.477 s 5√33 d. ≈ 2.611 s 11 e. Approx. 180.023 ft cos 2t + 5t + 29 4
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