34. Use the one-point test to solve 6x + 5y > 20. Shade the solution.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter1: Line And Angle Relationships
Section1.3: Introduction To Geometric Proof
Problem 36E: The Division Property of Inequality requires that we reverse the inequality symbol when dividing by...
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### Problem 34: Inequality Solution Using the One-Point Test

**Objective:** Solve the inequality \(6x + 5y > 20\) using the one-point test and visualize the solution by shading the appropriate region.

**Steps:**
1. **Graph the Boundary Line:** 
   - The inequality \(6x + 5y > 20\) will have a boundary line \(6x + 5y = 20\).
   - Convert to slope-intercept form for easier graphing:
     - \(5y = -6x + 20\)
     - \(y = -\frac{6}{5}x + 4\)

2. **Determine One-Point Test:**
   - Choose a test point not on the line, typically \( (0, 0) \) if it is not on the line.
   - Substitute \(x = 0\) and \(y = 0\) into the inequality:
     - \(6(0) + 5(0) > 20\)
     - \(0 > 20\) (False)
   - Since the point \((0, 0)\) does not satisfy the inequality, shade the region on the opposite side of the line.

3. **Shade the Solution:**
   - Shade the area where the inequality \(6x + 5y > 20\) holds true, which is the region that does not include the point \((0, 0)\).

By summarizing these steps, students will solve the inequality and shade the appropriate region to visualize the solution on a graph.
Transcribed Image Text:### Problem 34: Inequality Solution Using the One-Point Test **Objective:** Solve the inequality \(6x + 5y > 20\) using the one-point test and visualize the solution by shading the appropriate region. **Steps:** 1. **Graph the Boundary Line:** - The inequality \(6x + 5y > 20\) will have a boundary line \(6x + 5y = 20\). - Convert to slope-intercept form for easier graphing: - \(5y = -6x + 20\) - \(y = -\frac{6}{5}x + 4\) 2. **Determine One-Point Test:** - Choose a test point not on the line, typically \( (0, 0) \) if it is not on the line. - Substitute \(x = 0\) and \(y = 0\) into the inequality: - \(6(0) + 5(0) > 20\) - \(0 > 20\) (False) - Since the point \((0, 0)\) does not satisfy the inequality, shade the region on the opposite side of the line. 3. **Shade the Solution:** - Shade the area where the inequality \(6x + 5y > 20\) holds true, which is the region that does not include the point \((0, 0)\). By summarizing these steps, students will solve the inequality and shade the appropriate region to visualize the solution on a graph.
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