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31 (1)f (-6) = f (6) = 0 (2) f attains a minimum value of -9 (a) Part A Create a graph of f (x) Select the Parabola button. First, plot the vertex as Point A. Then, plot the positive z -intercept as Point B. 10 7. 5. 4. 3. 2. -1o -9 -8 -1 0 4. 10 -2 -3 -4 -5 -6 -7 -8 -9 1-10

31 (1)f (-6) = f (6) = 0 (2) f attains a minimum value of -9 (a) Part A Create a graph of f (x) Select the Parabola button. First, plot the vertex as Point A. Then, plot the positive z -intercept as Point B. 10 7. 5. 4. 3. 2. -1o -9 -8 -1 0 4. 10 -2 -3 -4 -5 -6 -7 -8 -9 1-10

Intermediate Algebra
Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter9: Quadratic Equations And Functions
Section9.7: Graph Quadratic Functions Using Transformations
Problem 362E: Graph the quadratic function f(x)=2x24x3 first using the properties as we did in the last section...
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3 There is a unique quadratic function in the form f (x) = ax +c that satisfies each of these cOndu (1) f (-6) = f (6) = 0 (2) f attains a minimum value of -9 (a) Part A Create a graph of f (x) Select the Parabola button. First, plot the vertex as Point A. Then, plot the positive x -intercept as Point B. 10 8 7 4 3 2. 1. -10 -9 -6 -5 -3 16 -2 -3 -4 -5 -6 -7 -8 -9 -10
Transcribed Image Text:3 There is a unique quadratic function in the form f (x) = ax +c that satisfies each of these cOndu (1) f (-6) = f (6) = 0 (2) f attains a minimum value of -9 (a) Part A Create a graph of f (x) Select the Parabola button. First, plot the vertex as Point A. Then, plot the positive x -intercept as Point B. 10 8 7 4 3 2. 1. -10 -9 -6 -5 -3 16 -2 -3 -4 -5 -6 -7 -8 -9 -10
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